Points: (5, -1) and (2, -5) Slope: 4/3 Perpendicular slope: -3/4
Points: (3,-1) and (-2, -5) Slope: 4/5
Point: (2, -1) Slope: -5 Equation: y = -5x+9
Slope is the change in y/change in x.So slope of the line passing through the points: (2,-1) & (0,4) isslope = [-1 - 4] / [2 - 0] = -5/2
let (2,-5) be P1 and (-1,-8) be P2 Slope is -5+8/2+1=3/3=1
The line perpendicular to a line with a slope of 1/5 has a slope of -5.
Points: (5, -1) and (2, -5) Slope: 4/3 Perpendicular slope: -3/4
Points: (2, 5) and (-1, 5) Slope: 0 and so therefore it has no slope but is a straight line parallel to the x axis
Answer:-10/2=-5Solution:The relation between the line slope and it's perpendicular line slope is negative reciprocal, i.e.Slope of the line perpendicular = -1/Slope of the line= -1/(2/10)= -1 x 10/2= -10/2= -5
The slope is (6 - 1)/(1 - 2) = 5/(-1) = -5
Endpoints: (-1, 1) and (1, 5) Slope: 2
Points: (2, 1) and (-4, -5) Slope: (1--5)/(2--4) = 1
The slope is -1 - 4 / -2 - 2 = -5/ -4 = 5/4
Points: (1, -1) and (5, -7)Slope: -3/2
Points: (3,-1) and (-2, -5) Slope: 4/5
Point: (2, -1) Slope: -5 Equation: y = -5x+9
Points: (1, 5) and (0, 2) Slope: 3