Point: (2, -1)
Slope: -5
Equation: y = -5x+9
y=2x+13
y = 2x - 1
It is: y = 2x-6
Another point is needed to work out the slope and its straight line equation. Slope is worked out as: (y2-y1)/(x2-x1) ----------------------- With slope m and going through a point (x0, y0), a line has equation: y - y0 = m(x - x0) Thus the point-slope equation of a line with slope m through the point (-1, 2) is given by: y - 2 = m(x - -1) → y - 2 = m(x + 1)
Points: (8, 10) and (-4, 2) Slope: 2/3 Equation: 3y = 2x+14
Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1, 1).
y-1 = 3(x - 2)
The equation of the line will also depend on its slope which has not been given and so an answer is not possible.
If you mean a point of: (2,1) then the equation works out as y = 3x-5
y = 2x + 1
Slope: -3 Point: (4, -5) Equation: y = -3x+7
y=3x-3
y=2x+13
Slope 3 and point of (-1, 4)Equation: y-4 = 3(x--1) => y = 3x+7
The answe iss..... 6
y = 2x - 1
It is: y = 2x-6