Given: P = 150 and L = (5W + 3) Solve the 'L' equation for 'W': (L-3) = 5W ===> W = (L-3)/5 Perimeter = 2L + 2W = 2L + 2[ (L-3)/5 ] = 2L + (2L-6)/5 5 x perimeter = 10L + (2L-6) = 12L - 6 Perimeter = 150 = (12L-6)/5 ===> 750 = (12L - 6) ===> 756 = 12L ===> L = 756/12 = 63=============================== Check: L = 63, W = 12, Perimeter = 2(L+W) = 2(63+12) = 2(75) = 150. Yay !
The figure could be a rectangle with length 4.73 and width 1.27(2dp). Area (A) of a rectangle = Length (L) x Width (W) = 6 : Then W = 6/L Perimeter = 2 (L + W) = 12 : substituting for W then :- 2(L + 6/L) = 12 : 2L + 12/L = 12 : 2L2 - 12L + 12 = 0 Solving for a quadratic equation gives L = (12 ± √48) ÷ 4 = 3 ± √3 = 3 ± 1.73 (2dp)
Multiply the width by length, e.g.10w x 12l 120sqft
Yes
12.000
Are you even trying, I could've done this when I was 6... 6x2 is 12L of water, 12L is 12000mL...
On an average 12L to 36L PA
12L
it's either 12L or 3,500 mL
L is side length so perimeter is 4L. If L is tripled the perimeter becomes 4 x 3L = 12L, so perimeter is also tripled.
24
0.335L*12L= 4.02L = 4020millilitres
It's not usually better than about 12l/100km.
12L x 1000= 12000 mL