0
What is the time period of simple pendulam which length is equal to radius of earth?
Wiki User
∙ 12y ago
If the pendulum was subject to earth surface gravity figure
Radius of earth = 6371000 metres (l)
acceleration due to gravity = 9.82 m/s/s (g)
>
t = 2 * pi * (square root ( l / g))
t = 5061 seconds (out and back to same point)
Wiki User
∙ 12y ago
Add your answer:
Earn +20 pts
How does one calculate arc length when given the radius and angle measure in degrees?
To find the arc length given the radius and angle measure in degrees, you must first convert the angle from degrees to radians, using the formula: Degrees = Radians X (pi/180). Then take the radians and the radius that you are given, and put them into the formula of Q = (a/r) where Q is the angle in radians, a is the arc length, and r is the radius. When you have this, simple multiply both sides by the radius to isolate the a. Once you do this, you have your answer.
Is it height x width x length?
It is a simple equation. It's length x width x height. That is a proper formula for volume.
How do you find the area of an oval?
well, an oval is a curved shape like the circle, so we use the same basic principle of πr² (or pi multiplied by (radius squared)). however, unlike the circle, the oval as two differing radii (plural of radius!) so we have to take that into account and adjust our formula accordingly. so the formula instead of squaring one radius, we measure both radii (horizontal radius * vertical radius) an then we multiply that by pi. the simple form of the formula is: π*(r1*r2) r1= horizontal radius r2= vertical radius π is the symbol for pi hope that helps!
Using the simple approximation above calculate the surface area of a sphere with a radius of 5 meter?
The surface area is approximately 300m²- APEX
How do you find an area of a segment of a circle?
The solution depends on the information supplied. Basically, you find the area of the sector containing the segment and then deduct the area of the triangle formed by the chord and the two radii enclosing the sector. If you are given the radius(r) of the circle and the height(h) then construct a radius that is perpendicular to and bisects the chord. This will create two congruent triangles which together form the main triangle. Using Pythagoras enables the half-chord length to be calculated as the hypotenuse is r and the height (also the length of the third side) is r-h. With this information the full chord length can be established and thus the area of the main triangle. Using sine or cosine methods enables the sector angle at the centre to be calculated and thus the sector area. Simple subtraction produces the area of the segment. If you are given the radius and the chord(c) length then the construction referred to above enables the height of the main triangle to be calculated and a similar process will generate the area of that triangle and the sector area. This, in turn, will enable the segment area to be determined.
How would the period of a simple pendulam affected if you conduct the simple pendulam experiment on moon?
Gravitatinal accelaration is low in moodn.Approximately 1/6 of Earth's accelaration.So periodic time increases.
What will happen to length of a simple pendulum if its time period is doubled?
time period of simple pendulum is dirctly proportional to sqare root of length...
How does the period of a pendulum difference theoretically with length for simple pendulum?
The period is directly proportional to the square root of the length.
How can you find effective length of a simple pendulum?
Measure the period, the period is directly proportional to the square root of the length.
What is the time period of a simple pendulum of infinite length?
∞
What error would be introduced by taking l equal to the length of the thread instead of correcting for the radius of the bob of a simple pendulum?
l would be too small and so the period would be too small.
In simple pendulum if string is flexible then what is effect on time period?
multiply the length of the pendulum by 4, the period doubles. the period is proportional to the square of the pendulum length.
How do the parameters of a simple pendulum affect the period of a pendulum?
The period increases as the square root of the length.
If length of simple pendulem increases constantly during osscillation then what is effct on time period?
the period of the pendulum increases with the square root of the length so if the length is four times, the period just doubles.
What would be the period of a pendulum with the length of 10 meters?
For a simple pendulum: Period = 6.3437 (rounded) seconds
What happens to the period of a simple pendulum if the pendulum length is doubled?
The period increases - by a factor of sqrt(2).
A simple pendulum of length 20cm took 120 seconds to complete 40 oscillation find its time period?
The period of a simple pendulum of length 20cm took 120 seconds to complete 40 oscillation is 0.9.
