ki where i is the unit horizontal vector, and k is any number.
Undefined slopes belong to lines that are vertical. These lines do not cross the y-axis, but do cross the x-axis. Therefore, the equation for these lines are always: x = # (where # is the value at which the line is crossing the x-axis).
y=-2.5 is parallel to the x axis. The equation of the x axis is y=0
[ y = plus or minus any number ] is parallel to the x-axis.
X=-b/2a
x=4
x=0
In 2 dimensions the angle made by the displacement vector with the positive x-axis is arctan(y/x).
You express a vector along the X-axis as a negative vector when the arrow representing the vector would point toward negative x.
At what angle should a vector be directed to so that its x component is equal to its y component
No, the axis must be specified: torque = (distance from the axis) X (force). (X is the vector cross-product in this case - meaning the angle also matters.)No, the axis must be specified: torque = (distance from the axis) X (force). (X is the vector cross-product in this case - meaning the angle also matters.)No, the axis must be specified: torque = (distance from the axis) X (force). (X is the vector cross-product in this case - meaning the angle also matters.)No, the axis must be specified: torque = (distance from the axis) X (force). (X is the vector cross-product in this case - meaning the angle also matters.)
A vector is a magnitude with a direction, so if you have a line that is +2 on the x-axis and +2 on the y-axis, that would be a vector.
When the arrow representing the vector would point toward negative x.
Sometimes denoted by -i.
J can be anything u want it to be...but typically j is a vector along y axis ( for example a point has vector equation i+3j+4k this mean that the point is 1 unit along x -axis (i) , 3 units along y-axis (j) , and 4 units along z-axis (k). )
Yes: such a vector would have only an x component, and it's change in regards to the y axis would be 0 (i.e. it would never get closer or farther from the y-axis).
Yes: such a vector would have only an x component, and it's change in regards to the y axis would be 0 (i.e. it would never get closer or farther from the y-axis).
Yes: such a vector would have only an x component, and it's change in regards to the y axis would be 0 (i.e. it would never get closer or farther from the y-axis).