113.1 cubic m
The surface area of a sphere with a radius of 5m is 314.2m2
Assuming that the charhe 'q' is uniformly distributed ina sperical volume of radius Discuss the variation of Electric intensity
The volume of a sphere that has a 14-meter diameter is 1,437 m3
Surface area of sphere: 4*pi*12^2 = 576*pi square m
52.36m3
Volume of a sphere is 4/3 pi times the cube of its radius.
Volume of the sphere: 4/3*pi*7.1^3 = 1499.214091 cubic m or about 1500 cubic m
If 8m is its radius then the volume of the sphere is: 4/3*pi*8^3 = 2145 cubic m rounded
To find the volume of the sphere that fits snugly inside a cube with 2.4 m edges, we first determine the radius of the sphere, which is half the edge length of the cube. Thus, the radius ( r ) is 1.2 m. The volume ( V ) of a sphere is given by the formula ( V = \frac{4}{3} \pi r^3 ). Plugging in the radius, the volume is approximately ( \frac{4}{3} \pi (1.2)^3 \approx 7.24 , \text{m}^3 ).
If they have the same radius then it is: 3 to 2
To find the mass of a sphere, you can use the formula ( m = \rho V ), where ( m ) is mass, ( \rho ) is the density of the sphere's material, and ( V ) is the volume. The volume of a sphere is calculated using the formula ( V = \frac{4}{3} \pi r^3 ), where ( r ) is the radius of the sphere. Once you have the volume, multiply it by the density to obtain the mass.
The ratio of surface area to volume for a sphere can be expressed using the formulas for surface area ( A = 4\pi r^2 ) and volume ( V = \frac{4}{3}\pi r^3 ). Therefore, the ratio ( \frac{A}{V} ) simplifies to ( \frac{3}{r} ). This means that the surface area to volume ratio decreases as the radius of the sphere increases. For a specific sphere with known surface area ( m ) and volume, you can calculate the ratio by finding the corresponding radius.
If the shape is a perfect sphere, then the ratio of surface area to volume will always be: 4πr2 / 4/3πr3 = 3/r If the volume = 500m3, then we can say: 500m3 = 4/3πr3 375m3 = r3 r = 5∛3 m So the ratio of surface area to volume on that sphere would be 3 / (5∛3 m), or: 3∛3/5m
==================================Answer #2:I believe you want the volume of the shell ... the material between theinside and outside diameters ... whereas the first answer, above, gave youthe volume of the hole in the middle of everything. Here's my take on it:-- Volume of a sphere is 4/3 pi R3-- Volume enclosed by the outer radius is 4/3 pi (2)3-- Volume enclosed by the inner radius is 4/3 pi (1)3-- Volume of the material between them is4/3 pi (23 - 13) = 4/3 pi x 7 =28/3 pi = 29.32 m3. (rounded)The volume of a spherical shell is equal to the difference between the volume of a sphere with a radius of 2 m and a volume of a sphere with a radius of 1 meter:V= 29,321531433504736892318004910609 м3
Volume of the sphere: 4/3*pi*2^3 = 33.5 cubic meters to one decimal place
The volume of a sphere is (4/3)*pi*(r^3), where r is the radius. Solving for r: (4/3)*pi*(r^3) = 268 (r^3) = 268/((4/3)*pi) r = cube root(268/((4/3)*pi)), which is approximately cube root (63.98), which is approximately, 4.00 m.
The formula for the surface area of a sphere is 4πr² and the formula for the volume is (4/3)πr³, where r is the radius of the sphere. Setting 4πr² equal to 588 and (4/3)πr³ equal to 1372, you can solve for the radius by equating the two expressions and taking the cube root of the result. Once you have the radius, you can calculate the surface area using the formula and divide it by the volume to find the ratio.