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Assuming the equation of the given line is y = 3x + 4, its gradient is 3.Therefore the gradient of the required line is 3.

The line passes through (3, 1) and so its equation is

y - 1 = 3*(x - 3) = 3x - 9

So y = 3x - 8

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8y ago
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8y ago

If you mean: y = 3x+4

Then the parallel line is: y = 3x-8 or 3x-8-y = 0

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Q: What is the written equation of a line in standard form that passes through the point 3 1 and is parallel to the line y 3x plus 4?
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