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Subjects>Math>Geometry

What is the x and y intercepts of 5x-7y equals -35?

Anonymous

∙ 15y ago

Updated: 4/28/2022

5x - 7y = -35

At the x-intercept, y=0:

5x = -35

x = -7

At the y-intercept, x=0:

-7y = -35

y = 5

Wiki User

∙ 15y ago

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Q: What is the x and y intercepts of 5x-7y equals -35?

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What represents the vertex and two x-intercepts of y equals x2-2x-35?

(1,-36); -5 and 7y = x2-2x-35; f(x) = ax2+bx+cvertex, method 1:There is a formula for the vertex, if you can remember it. (h,k) = [-b/2a, f(-b/2a)].-b/2a = 2/2x1 = 2/2 = 1. f(1) = 12-2x1-35 =1-2-35 = -36. The vertex is (1,-36).vertex, method 2:Otherwise you complete the square to convert to the vertex form, y = a(x-h)2 + k. Complete the square for x2-2x: the constant term will be (-2/2)2 = (-1)2 = 1.y = (x2-2x+1)-1-35 = (x-1)2 -36 ==> The vertex is (h,k) = (1,-36).x-intercepts, method 1:To find the x-intercepts, let y=0: 0 = x2-2x-35 (x-7)(x+5) = 0 x-7=0 or x+5=0 x=7 or x=-5. The intercepts are -5 and 7.x-intercepts, method 2:There is also a nice trick to find the intercepts: 36 = 62. the intercepts are 1+/- 6 = 7 and -5.

What are the intercepts of 2x 3y-6z equals 30?

x: x = 15 y: y = 10 z: z = -5

Find the coordinates of the x and y intercepts of -5x plus 6y equals 30?

-5x + 6y = 30At the x-intercept, y=0:-5x = 30 ==> x = -6At the y-intercept, x=0:6y = 30 ==> y = 5

What is the x and y intercepts in y plus 4 equals 0?

y + 4 = 0 y = 0x - 4 The graph is a straight horizontal line. Its slope is zero. The y-intercept is -4. There is no x-intercept.

What is the relationship between the vertex and the x intercepts?

In general, there is no relationship.

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What is the intercept of the equation y equals -x?

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Find the slope and intercepts of each line y equals -x plus 1000?

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What is y equals -x using intercepts?

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What is the x-intercepts y equals 2x2 plus 2x - 4?

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What represents the vertex and two x-intercepts of y equals x2-2x-35?

(1,-36); -5 and 7y = x2-2x-35; f(x) = ax2+bx+cvertex, method 1:There is a formula for the vertex, if you can remember it. (h,k) = [-b/2a, f(-b/2a)].-b/2a = 2/2x1 = 2/2 = 1. f(1) = 12-2x1-35 =1-2-35 = -36. The vertex is (1,-36).vertex, method 2:Otherwise you complete the square to convert to the vertex form, y = a(x-h)2 + k. Complete the square for x2-2x: the constant term will be (-2/2)2 = (-1)2 = 1.y = (x2-2x+1)-1-35 = (x-1)2 -36 ==> The vertex is (h,k) = (1,-36).x-intercepts, method 1:To find the x-intercepts, let y=0: 0 = x2-2x-35 (x-7)(x+5) = 0 x-7=0 or x+5=0 x=7 or x=-5. The intercepts are -5 and 7.x-intercepts, method 2:There is also a nice trick to find the intercepts: 36 = 62. the intercepts are 1+/- 6 = 7 and -5.

Why does y equals 0 when solving a quadratic equation?

Because when your solving a quadratic equation your looking for x-intercepts which is where why equals 0 and x equals what ever the answer is.

How many x intercepts does the graph of y equals x2 have?

One. It is a double root.

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