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What represents the vertex and two x-intercepts of y equals x2-2x-35?
(1,-36); -5 and 7y = x2-2x-35; f(x) = ax2+bx+cvertex, method 1:There is a formula for the vertex, if you can remember it. (h,k) = [-b/2a, f(-b/2a)].-b/2a = 2/2x1 = 2/2 = 1. f(1) = 12-2x1-35 =1-2-35 = -36. The vertex is (1,-36).vertex, method 2:Otherwise you complete the square to convert to the vertex form, y = a(x-h)2 + k. Complete the square for x2-2x: the constant term will be (-2/2)2 = (-1)2 = 1.y = (x2-2x+1)-1-35 = (x-1)2 -36 ==> The vertex is (h,k) = (1,-36).x-intercepts, method 1:To find the x-intercepts, let y=0: 0 = x2-2x-35 (x-7)(x+5) = 0 x-7=0 or x+5=0 x=7 or x=-5. The intercepts are -5 and 7.x-intercepts, method 2:There is also a nice trick to find the intercepts: 36 = 62. the intercepts are 1+/- 6 = 7 and -5.
What are the intercepts of 2x 3y-6z equals 30?
x: x = 15 y: y = 10 z: z = -5
Find the coordinates of the x and y intercepts of -5x plus 6y equals 30?
-5x + 6y = 30At the x-intercept, y=0:-5x = 30 ==> x = -6At the y-intercept, x=0:6y = 30 ==> y = 5
What is the x and y intercepts in y plus 4 equals 0?
y + 4 = 0 y = 0x - 4 The graph is a straight horizontal line. Its slope is zero. The y-intercept is -4. There is no x-intercept.
What is the slope and y-intercept of the line given by the equation y equals -5x?
The slope is -5. The x- and y-intercepts are both zero. In other words, it passes through the origin.
Find -x when x equals 35?
If x equals 35, then -x equals -35.
What are the x-intercepts and Y-intercepts for the graph 3x plus 15 equals 5y?
X intercept: -5 Y intercept: +3
How do you find the intercepts of F of X equals 6000 - 75x?
It is 6000.
How do you find the numbers x-intercepts of function y equals 5x'2?
5x²=0 X=0 the function y=5x² only intercepts x when x = 0
What is the intercept of the equation y equals -x?
The 'x' and 'y' intercepts of that equation are both at the origin.
What represents the vertex and two x-intercepts of y equals x2-2x-35?
(1,-36); -5 and 7y = x2-2x-35; f(x) = ax2+bx+cvertex, method 1:There is a formula for the vertex, if you can remember it. (h,k) = [-b/2a, f(-b/2a)].-b/2a = 2/2x1 = 2/2 = 1. f(1) = 12-2x1-35 =1-2-35 = -36. The vertex is (1,-36).vertex, method 2:Otherwise you complete the square to convert to the vertex form, y = a(x-h)2 + k. Complete the square for x2-2x: the constant term will be (-2/2)2 = (-1)2 = 1.y = (x2-2x+1)-1-35 = (x-1)2 -36 ==> The vertex is (h,k) = (1,-36).x-intercepts, method 1:To find the x-intercepts, let y=0: 0 = x2-2x-35 (x-7)(x+5) = 0 x-7=0 or x+5=0 x=7 or x=-5. The intercepts are -5 and 7.x-intercepts, method 2:There is also a nice trick to find the intercepts: 36 = 62. the intercepts are 1+/- 6 = 7 and -5.
What is y equals -x using intercepts?
y = -xBoth intercepts are at the origin. From there, the line slopes up to the leftand down to the right.
Find the slope and intercepts of each line y equals -x plus 1000?
Slope: -1 intercepts: (0,1000),(1000,0)
What is the x-intercepts y equals 2x2 plus 2x - 4?
For the x intercepts, y = 0 ie 0 = 2x2 + 2x - 4 or x2 + x - 2 = 0 so that (x + 2)*(x - 1) = 0 So the intercepts are (-2,0) and (1,0)
What are the x and y intercepts of Y equals 2X plus 24?
12
Why does y equals 0 when solving a quadratic equation?
Because when your solving a quadratic equation your looking for x-intercepts which is where why equals 0 and x equals what ever the answer is.
How many x intercepts does the graph of y equals x2 have?
One. It is a double root.
