x: x = 15
y: y = 10
z: z = -5
2x + 30 = 4x + 22 Subtracting 2x from both sides, 30 = 2x + 22 Subtracting 22 from both sides, 8 = 2x Dividing both sides by 2, 4 = x x = 4
-5x + 6y = 30At the x-intercept, y=0:-5x = 30 ==> x = -6At the y-intercept, x=0:6y = 30 ==> y = 5
X=30 2x+2x+x+30=180; All of the angles in a triangle always add up to 180. Therefore 5x+30=180; subtract 30 to be 5x by itself. Therefore 5x=150; divide by 5 to find x. Therefore X=30 2(30)+2(30)+30+30=180
First we have to find the width. Let the width be x: 2(12+x) = 30 24+2x = 30 2x = 30-24 2x = 6 x = 3 So the width is 3 units Area = length*width = 12*3 = 36 square units
30
The intercepts of 2x + 3y - 6z = 30 are(15, 0, 0), (0, 10, 0) and (0, 0 , -5).
The intercepts of 2x + 3y - 6z = 30 are(15, 0, 0), (0, 10, 0) and (0, 0 , -5).
To find the intercepts of the equation (2x + 3y - 6z = 30), we set two variables to zero at a time. For the x-intercept, set (y = 0) and (z = 0): (2x = 30) gives (x = 15). For the y-intercept, set (x = 0) and (z = 0): (3y = 30) gives (y = 10). For the z-intercept, set (x = 0) and (y = 0): (-6z = 30) gives (z = -5). Thus, the intercepts are ( (15, 0, 0) ), ( (0, 10, 0) ), and ( (0, 0, -5) ).
To find the x-intercept of the equation (2x + 3y = 30), set (y = 0): (2x = 30), giving (x = 15). For the y-intercept, set (x = 0): (3y = 30), resulting in (y = 10). Therefore, the x-intercept is (15) and the y-intercept is (10).
12
12x - 5(2x - 6) = 30 12 x - 10x + 30 = 30 2x = 0, x = 0 y = -6
2x-17=13 2x=30 x=15
2x - 10 =30 2x -10 = 30 +10 +10 2x = 40 /2 /2 x = 20
Substitute 2x - 6 for y in first equation: 12x - 5(2x - 6) = 30 ie 12x - 10x + 30 = 30 so 2x = 0 making x = 0 and y = -6
x=6 y=30
2x-5=25 2x=25+5 x=30/2 x=15
x=6.