There are many possibilities.
One is a rectangle with length 9.60555128 and breadth 2.39444872 units (to 8 dp).
24
The perimeter is 24 feet.
24
To find the perimeter of a shape with an area of 480 square feet, you first need to know the shape's dimensions. For example, if you consider a rectangle, the area can be calculated as length multiplied by width (A = length × width). If you take a rectangle with dimensions of 20 feet by 24 feet, the perimeter would be 2(length + width) = 2(20 + 24) = 88 feet. Other shapes will yield different perimeters for the same area depending on their dimensions.
Perimeter = 24 inches Area = 35 square inches
The area of a hexagon with a perimeter of 24 feet is about 41.6 square feet.
A 5 x 7 rectangle
When the area of a square is 36cm2, its perimeter is: 24 cm
Perimeter = 24 and area = 27 . . . . . rectangle, 3 by 9 Perimeter = 32 and area = 15 . . . . . rectangle, 1 by 15
24
A square with a perimeter of 24 cm has an area of: 36 cm2
The area of a regular hexagon with a 24-inch perimeter is about 41.57 square inches.
Depending on the figure given you can find the area from the perimeter For example- If you have a square with a perimeter of 24, you divide 24 by 4 because all the sides of a square are congruent. In turn you will 6 as each side of the square The formula for the area of a square is side2 so you get 62 which is 36. The area is 36
24
The perimeter is 24 feet.
If it's a square, the perimeter is 24.
. What is the greatest area possible enclosed by a quadrilateral with a perimeter of 24 feet?