The possible answer, with the dividing plane being perpendicular to the faces are:
The number of possibilities increased greatly if the dividing plane can be oblique.
I am not 100% sure but I think the most polygons in it is a hexagon since its a hexagonal prsim....
sqare
6 rectangles an 2 hexagon * * * * * A hexagonal prism.
I think it's 3 triangles and 1 rectangle but, I'm only in 6th grade.
From each vertex, N-4 diagonals can be drawn, where N is the number of vertices. The total number of diagonals in a prism will be N(N-4)/2, where N is the number of vertices. For N=12 (a hexagonal prism) The total number of diagonals is 12*8/2=48 Answer:48
Two hexagons and six rectangles
A hexagon and a rectangle.
I am not 100% sure but I think the most polygons in it is a hexagon since its a hexagonal prsim....
sqare
hexagonal prism, a cone, and i believe circle or cylinder
Tow triangles and three rectangles.
Two pentagons and five rectangles.
A trianglular prism is made up of triangles and rectangles, so its net must have the same shapes.
2 octagons (floor and roof), 8 rectangles (walls).
There are six rectangles, consisting of three pairs of congruent rectangles.
Squared. When you find surface area, you are only finding the area of the shapes that make up the three-denominational shape.
6 rectangles an 2 hexagon * * * * * A hexagonal prism.