Yes, it does.
It does.
Do you mean the following? (x + 16)2 + (y + 3)2 = 17 (x + 3)2 + (y - 6)2 = 44 You can find the center of these circles by using the negatives of the numbers subtracted by the x and y variables. In this case, the circles are centered at the points (-16, -3) and (-3, 6). The one in which both the x and y co-ordinates are negative would be the one in the third quadrant. And try to phrase your questions better. That could just as easily be read as "ax + 162 + y + 32 = 17bx + 32 + y - 62 = 44", which makes no sense.
The question asks about the "following". In those circumstances would it be too much to expect that you make sure that there is something that is following?
Farmers had more control over their crops than with sharecropping.
A pair of compasses are use to construct circles and arcs of circles
The one in which the centre is in the fourth quadrant, and where the distance from the centre of the circle to the origin is greater than its radius.
clarify your question a bit man !
When the centers of both the circles are at the same point.
They're circles that may have different sizes but their centers are at the same point.
They are the common tangents to the circles.
it intersects the segment joining the centers of two circles
A square does have a centre.
you draw a triangle formed by the centers of the two circles and use pythagoean theorem
Yes, that is correct. Circles circumscribed about a given triangle will have centers that are equal to the incenter, which is the point where the angle bisectors of the triangle intersect. However, the radii of these circles can vary depending on the triangle's size and shape.
False
For Ellipse: The 2 circles made using the the ellipse center as their center, and major and minor axis of the ellipse as the dia.For Hyperbola: 2 Circles with centers at the center of symmetry of the hyperbola and dia as the transverse and conjugate axes of the hyperbolaRead more: eccentric-circles
Not necessarily. It doesn't matter where their centers are. In order to be congruent, they must have the same radius. On the subject of having the same center . . . the hubcap and the tire are not congruent.
To find the differential equation of a family of circles passing through the origin and having centers on the x axis one needs to have a variable to compare it to. To best find this answer one might enlist the help of a math professor as well.