you draw a triangle formed by the centers of the two circles and use pythagoean theorem
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it intersects the segment joining the centers of two circles
You times it by 2....UR WELCOME
196-164/2= 16
-pi/2 and pi/2
mostly it comes from memorization. If sin 30 = 1/2, then arcsin (1/2) = 30
it intersects the segment joining the centers of two circles
[1+(y')2]3 = [yy"+1+(y')2]2
Hey, this one is nice! I will venture the following: * 3: make them tangent in one point, with no intersection * 2: make them have a small intersection, ie. crossing in two points * 1: make them tangent from the inside * 0: make one fall completely within the other Giving the explanation would just be killing the imagination.
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The question is suppose to read: Find the equation of the line tangent to y=(x²+3x)²(2x-2)³, when x=8
You times it by 2....UR WELCOME
196-164/2= 16
236-124/2=56 degrees
The shape you are describing is called a "stadium" or a "racetrack" shape. It consists of a rectangle with two semicircles attached at each end. This shape is often used in architecture and engineering for design and structural purposes.
The arc tangent is the recicple of the tangent which is also known as the cotangent. The tangent of π/2 is undefined, thus the cotangent would be zero.
They are used to find the angle or side measurement of a right triangle. For example, if 2 sides of a right triangle have known values and an angle has a known measurement, you can find the third side by using sine, cosine or tangent.
the length of thr direct common tangent will be 2*{1/2 power of (r1*r2)} the answer will be 8 units in this case...