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Why is product of slopes of x axis and y axis not equal to one?
Wiki User
∙ 15y ago
We know that the slope of a line is (Changes in y)/(Changes in x).
Does the y-axes has changes in y? No. This means that y-axis does not have a slope. The same thing is for x-axis.
Wiki User
∙ 15y ago
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If two lines are parallel what do you know about their slopes?
If two lines are parallel, they have the same slope.(And if they are perpendicular, the product of their slopes is minus one - unless one line is horizontal and the other vertical.)
What is the difference between slopes of parallel lines and slopes of perpendicular lines?
Slopes of parallel lines have the same slope (they are changing at the same rate).Slopes of perpendicular lines have slopes that are the negative inverse of each other, that is, their product is -1. (The slope of a vertical line is therefore undetermined, not infinity. There is no slope s that times 0 equals -1.)---Let m1 be the slope of line one and m2 be the slope of line two. Then:If the lines are parallel, then their slopes are equal, so m1 - m2 = 0.If the lines are perpendicular, then their slopes are negative inverses of each other, so= m1 - (-1/m1)= m1 + 1/m1= (m12 + 1)/m1
Why is the product of the slopes of perpendicular lines always negative?
Yes the product will be negative, in fact the product will equal negative one (-1). Think about this. Suppose you have a line y = mx + b, and you want to rotate it 90° counterclockwise. This new line would be like in a coordinate system (x',y') [the x' and y' are called x-prime and y-prime, and differentiate between the original and new coordinate system], where the x' axis runs along the y axis in the positive y direction, and the y' axis runs along the x axis in the negative x direction. So the new line y' = mx' + b with x' = y and y' = -x, is: -x = my + b. Solving for y in the new equation gives y = (-1/m)x - (b/m). So the new slope (-1/m) times the original slope (m) equals (-m/m) = -1, as long as the original slope was not zero.
Which is y and which is x axis?
Y axis is usually the vertical one and x is the horizontal one.
What is tangent to the x axis?
Well, since a tangent line touches a line in one spot, the Y axis could be considered tangent to the X axis.
How do slopes of perpendicular lines compare?
Slopes of perpendicular lines will be opposite reciprocals. This means that the slopes have opposite signs and that one is 1/ the other. For example, 2 and -1/2.
If the product of the slopes is what then the lines are what?
If the product is -1 then the lines are perpendicular to one another.
What does it mean when a graph slopes up in economics?
It means that the variable plotted on the vertical axis increases as the one plotted on the horizontal axis increase.
If two lines are parallel what do you know about their slopes?
If two lines are parallel, they have the same slope.(And if they are perpendicular, the product of their slopes is minus one - unless one line is horizontal and the other vertical.)
Definition of slopes of perpendicular lines?
One is the negative reciprocal of the other. That is, the product of the two slopes is -1. UNLESS one of them is zero, in which case the slope of the other is infinite.
If the product of the slopes of two lines equals -1 then the lines?
Are perpendicular to one another.
Do two lines that have slopes of 1 and -1 are perpendicular?
2
How do you use slope to determine if two lines are perpendicular?
You have to know the slopes of both lines. -- Take the two slopes. -- The lines are perpendicular if (one slope) = -1/(the other slope), or the product of the slopes equals to -1.
In a coordinate plane two nonvertical lines are WHAT if and only if the product of their slopes is negative one?
Perpendicular
Which formula is correct for the slopes of perpendicular lines?
if slope is given as m then perpendicular slope is -1/m (negative inverse)
Is a season equal to one spin of the earth on its axis?
no
What is the difference between slopes of parallel lines and slopes of perpendicular lines?
Slopes of parallel lines have the same slope (they are changing at the same rate).Slopes of perpendicular lines have slopes that are the negative inverse of each other, that is, their product is -1. (The slope of a vertical line is therefore undetermined, not infinity. There is no slope s that times 0 equals -1.)---Let m1 be the slope of line one and m2 be the slope of line two. Then:If the lines are parallel, then their slopes are equal, so m1 - m2 = 0.If the lines are perpendicular, then their slopes are negative inverses of each other, so= m1 - (-1/m1)= m1 + 1/m1= (m12 + 1)/m1
