Yes the product will be negative, in fact the product will equal negative one (-1).
Think about this. Suppose you have a line y = mx + b, and you want to rotate it 90° counterclockwise. This new line would be like in a coordinate system (x',y') [the x' and y' are called x-prime and y-prime, and differentiate between the original and new coordinate system], where the x' axis runs along the y axis in the positive y direction, and the y' axis runs along the x axis in the negative x direction. So the new line y' = mx' + b with x' = y and y' = -x, is: -x = my + b. Solving for y in the new equation gives y = (-1/m)x - (b/m). So the new slope (-1/m) times the original slope (m) equals (-m/m) = -1, as long as the original slope was not zero.
It is always -1.
Negative reciprocal slopes always represent perpendicular lines.
Are perpendicular.
They are perpendicular if the product of their slopes is -1.
When the perpendicular lines are horizontal and vertical.
If the lines are perpendicular, their slopes are negative reciprocals.If the lines are perpendicular, their slopes are negative reciprocals.If the lines are perpendicular, their slopes are negative reciprocals.If the lines are perpendicular, their slopes are negative reciprocals.
It is always -1.
-1
Negative reciprocal slopes always represent perpendicular lines.
Are perpendicular.
I believe they have Negative Slopes as stated by my Geometry Book. "Perpendicular Lines Have Slopes Which Are Negative ___"
Perpendicular
Two numbers are negative reciprocals if their product is -1. The numbers 1/2 and -2 are negative reciprocals. Their product is -1. This is often seen in problems involving the slopes of two lines. The slopes of perpendicular lines are negative reciprocals. Their product is -1.
They are perpendicular if the product of their slopes is -1.
One is the negative reciprocal of the other. That is, the product of the two slopes is -1. UNLESS one of them is zero, in which case the slope of the other is infinite.
negative reciprocal slopes ---> the lines are perpendicular equal slopes ---> the lines are parallel
Yes, as long as the negative slopes are both equal.