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Actually it IS. perpendicular lines have opposite reciprocal slopes and parallel lines have the same slope.
Slopes of line perpendicular to the x-axis are undefined.
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Two lines are perpendicular if the product of their slopes is -1. A straight line with an equation in the form: y = mx + c has slope m and y-intercept c. Given two lines y = mx +c and y = nx + d they are perpendicular if mn = -1. Examples: 1) are the two lines y = 2x and 2y = x + 2 perpendicular? y = 2x 2y = x + 2 → y = 1/2 x + 1 → product of slopes = 2 x 1/2 = 1 → the lines are not perpendicular 2) are the two lines y + 2x = 5 and 2y = x + 2 perpendicular? y + 2x = 5→ y = -2x + 5 2y = x + 2 → y = 1/2 x + 1 → product of slopes = -2 x 1/2 = -1 → the lines are perpendicular
It is always -1.
If the product is -1 then the lines are perpendicular to one another.
Negative reciprocal slopes always represent perpendicular lines.
Take any two lines and look at their slopes. -- If the slopes are equal, then the lines are parallel. -- If the product of the slopes is -1, then the lines are perpendicular.
When the perpendicular lines are horizontal and vertical.
Are perpendicular.
If the lines are perpendicular, their slopes are negative reciprocals.If the lines are perpendicular, their slopes are negative reciprocals.If the lines are perpendicular, their slopes are negative reciprocals.If the lines are perpendicular, their slopes are negative reciprocals.
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You have to know the slopes of both lines. -- Take the two slopes. -- The lines are perpendicular if (one slope) = -1/(the other slope), or the product of the slopes equals to -1.
Are perpendicular to one another.
In that case, the product of the slopes is equal to minus 1.
The sum of their slopes is 0. The product of two lines that are perpendicular with slopes m and -m i= -m^2 Hmmmm... Seems we're both wrong again. The answer is -1. See the link I attached.