perpendicular to y = 2x + 3, y-intercept is 5.
the answer is y = -½x + 5
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-3x+9=y
The slope-intercept form of an equation is: y = mx + b Just copy down this equation, then replace "m" with the slope, and "b" with the y-intercept.
-7
The slope of x and the y intercept as for example in the straight line equation of y = 2x+3 the slope is 2 and the y intercept is 3
8
y = x
As for example the perpendicular equation to line y = 2x+6 could be y = -1/2x+6 because the negative reciprocal of 2x is -1/2x
"Y = any number" is perpendicular to "x = -3".
No, you need either two points, one point and a slope, one point and a y-intercept, or a y-intercept an a slope. You can also write the equation of a line with an equation of another line but you would have to know if it is parallel or perpendicular.
-3x+9=y
y=2/3x-7
y = -x + 8
15
By including the + or - signs in the question
-12
It is a straight line equation and can be rearranged into slope intercept form as follows:- 6x-6y = 12 -6y = -6x+12 y = x-2 which is now in slope intercept form
The given equation is : x + 5 + y = 0 Write in standard form of equation of straight line : y = mx + c . Where m is slope and c is y-intercept. We get: y = -x - 5 Which gives slope = -1 y-intercept = -5 To get x-intercept put y = 0 in the equation. We get x-intercept = -5