Wiki User
∙ 15y ago-3x+9=y
Wiki User
∙ 15y agoThere are infinitely many lines perpendicular to this line. All of them have the slope of -4/3, if that fact is of any help to you.
negative 1
If you mean: y = 3/4x-0.5 then the perpendicular equation could be y = -4/3x-5
if a line has a slope of -2 and a point on the line has coordinates of (3, -5) write an equation for the line in point slope form
Convert the equation 2y = 5x - 4 into standard form then y = 2.5x - 2. Two straight lines are perpendicular if the product of their gradients is -1. Let the equation of the perpendicular line by y = mx + b. Then, 2.5m = -1 : m = -1/2.5 The y intercept occurs when x = 0. Then -3 = 0 + bc : b = -3 The equation of the perpendicular line is y = -1/2.5x -3 or 5y = -2x -15
You can write it either in standard form (ax + by = c) or in slope-intercept form (y = mx + b)
"Y = any number" is perpendicular to "x = -3".
Take the negative reciprocal of the lines slope you want it to be perpendicular to. For example y = 3x +2; perpendicular line slope is -1/3.
As for example the perpendicular equation to line y = 2x+6 could be y = -1/2x+6 because the negative reciprocal of 2x is -1/2x
No, you need either two points, one point and a slope, one point and a y-intercept, or a y-intercept an a slope. You can also write the equation of a line with an equation of another line but you would have to know if it is parallel or perpendicular.
15
y = -x + 6
It would be perpendicular to a line with the equation Y = 1/8 X.
Yes, I could, if I knew the slope of the line given.
Solve the line equation for "y", to get it in slope-intercept form. You can immediately read the slope from this equation.Divide -1 by (slope of this first line) to get the slope of the second line - the one perpendicular to the given line. Write an equation for any line with this slope.
Line B is perpendicular to Line A if its slope is the negative reciprocal of the slope of Line A.When a linear equation is in the formy = mx + b,m is the slope, and b is the y-intercept. So, for example,y = (2/3)x + 5is perpendicular toy = (-3/2)x + 7.(The y-intercepts in these two equations are random numbers.)
Without the inclusion of an equality sign and not knowing the plus or minus values of the given terms it can't be considered to be a straight line equation