x = 1
Vertical: x = 5Horizontal: y = 4Vertical: x = 5Horizontal: y = 4Vertical: x = 5Horizontal: y = 4Vertical: x = 5Horizontal: y = 4
Y = X2 ===== This is a parabolic function because it passes the vertical line test. ( you should know what that test is )
Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).
Undefined slopes belong to lines that are vertical. These lines do not cross the y-axis, but do cross the x-axis. Therefore, the equation for these lines are always: x = # (where # is the value at which the line is crossing the x-axis).
Write an algorithm to find the root of quadratic equation
The formula for a line is: Y = mX + b
Any vertical line has an undefined slope. The equation of the vertical line is x = a where the x-intercept is a.
Y=4x+3
It is: y = 5x+6
The equation of every vertical line is [ X = the value of 'x' where the line crosses the x-axis ].
It would be y = 6x.
Vertical: x = 5Horizontal: y = 4Vertical: x = 5Horizontal: y = 4Vertical: x = 5Horizontal: y = 4Vertical: x = 5Horizontal: y = 4
A vertical line has the equation [ x = a number ]. A horizontal line has the equation [ y = a number ].
y=3x+b -2=3*5+b b=-17 y=3x-17
Write the equation of the line that passes through the points (3, -5) and (-4, -5)
A vertical line has the equation x = C (a constant value), where y has all values, x has only one value, and the slope is undefined (the run, Δx, is zero, so you cannot divide the rise by the run).
Y = X2 ===== This is a parabolic function because it passes the vertical line test. ( you should know what that test is )