yes it is untrue and true at the sametime
AX + BY is not an equation .AX + BY + C = 0is the general equation for a straight line.
Solution:(5r0)2 - (1r1+0r0)*5 + 3r1+1r0 = (8r0)2 - (1r1+0r0)*8 + 3r1+1r0 25 - 5r + 3r + 1 = 64 - 8r + 3r + 13r - 39 = 0r = 13Result: radix r = 13
There is no "most advanced" math equation, just as you can never count to "infinity".The equation eipi + 1 = 0is certainly an amazing relationship.(e is 2.7828 ... , i is the solution to i2 = -1, and pi is 3.14159 ...)
the ampere i=0is theonlyedge where the e0b and e0c can come together and share the load and that way the two vector diagrams will connected and the load will be less resistive and more on the ek0 and c73 resistive load. the 38f93 relay will be the one to break the load 2u3 and e0b and e0c into diffrent components that will be drawn in the diagram.
If a value for a variable "satisfies an equation", that means that when a variable is replaced by the value, the equation is true (same values on the left and on the right).Some equations have a single solution (a single value that satisfies the equation), for example:x + 1 = 5will only be true if x is replaced with 4. A quadratic equation quite often has two solutions, for example:x2 - 5x + 6 = 0is true for x = 2, and for x = 3. A polynomial of degree n can have up to n solutions. A trigonometric equation, such as sin(x) = 0, often has an infinite number of solution, due to its periodic nature.
Sure, there are many. A couple of simple examples would be:x = (9 - 8) * (7 - 6) * (5 - 4) * (3 - 2) * (1 - 0)x = 9 - 8 - 7 + 6 + 5 - 4 - 3 + 2 + 1 - 0You're not limited with that though. Consider: any value other than zero, when raised to the power of zero, is equal to 1. This means that you can take any combination of the other numbers, and as long as they are not equal to 0, then you can raise them to the power of zero to get an end result of 1. For example this equation:x = [√7 * 2 / 65 + 8 - ∫13(4x9)dx]0is just as valid as the ones given above.
x2 - x = 0 ?simplifying to the initial equation by grouping of terms:x(x-1) = 0is true when x = 1 or x = 0by the quadratic formula we can find the root (solution) of the equation as follows:the equation can be rewritten as(1(x2)) - (1(x)) + 0 = 0so that we can see the form ax2 + bx +c = 0Substituting our values for a, b and c into the formula, we getx = (-b ± √(b2 - 4ac)) ÷ 2ax = (-(-1) ± √(-12 - 4x1x0)) ÷ (2 x 1)x = (-(-1) ± √(1 - 0)) ÷ 2x = (1 ± 1) ÷ 2x = 2 ÷ 2 = 1ORx = 0 ÷ 2 = 0i.e. the roots (solution) of the equation x2 - x = 0 ? are when x = 1 or x = 0