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x2 - x = 0 ?

simplifying to the initial equation by grouping of terms:

x(x-1) = 0

is true when x = 1 or x = 0

by the quadratic formula we can find the root (solution) of the equation as follows:

the equation can be rewritten as

(1(x2)) - (1(x)) + 0 = 0

so that we can see the form ax2 + bx +c = 0

Substituting our values for a, b and c into the formula, we get

x = (-b ± √(b2 - 4ac)) ÷ 2a

x = (-(-1) ± √(-12 - 4x1x0)) ÷ (2 x 1)

x = (-(-1) ± √(1 - 0)) ÷ 2

x = (1 ± 1) ÷ 2

x = 2 ÷ 2 = 1

OR

x = 0 ÷ 2 = 0

i.e. the roots (solution) of the equation x2 - x = 0 ? are when x = 1 or x = 0

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Wiki User

12y ago

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(x-7)(x+7)

but what if the question was

x squared PLUS 49

x^2 + 49

help

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16y ago
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x2-25 = (x-5)(x+5) when factored

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12y ago
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That factors to (x - 14)(x + 14)

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8y ago
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0.0000

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Anonymous

4y ago
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