if it's this like this 42+n/4=? and n=8firstly u should do the 8 divided by 4 then do the other functions42+8/4=42+2=44
it has adkdgbsgbsd'g SD
The question seems ambigous, but I will consider n 2n to be solving for n:2n - 3n = n/3 + 14-n = n/3 + 14-3n = n + 42-4n = 42Thus, the solution is n = -42/4 = -21/2 = -10.5.
If you mean: n^2 -13n +42 then it equals (n -6)(n -7) when factored
Three consecutive even numbers can be expressed as (x) + (x + 2) + (x + 4), where x is the least of the three numbers. If these three add to 42 then it can be said that: (x) + (x + 2) + (x + 4) = 42 This leads to: 3x + 6 = 42, which results in 3x = 36. So x = 12. This means that numbers are 12, 12+2, and 12+4. The answer is 12, 14, and 16. To double check, 12 + 14 + 16 = 42.n+(n+2)+(n+4)=423n+6=423n=36n=1212, 14, 16
if it's this like this 42+n/4=? and n=8firstly u should do the 8 divided by 4 then do the other functions42+8/4=42+2=44
n11 / n8 = n(11-8) = n3
3
it has adkdgbsgbsd'g SD
Latitude: N 42° 4' 0.786"
6n = 42 n = 42/6 n = 7
Latitude: N 42° 4' 0.786"
N8
N8.
n8
3n + 4n = 42 7n = 42 n = 42/7 n = 6
The factors of n12 are 1, n, n2, n3, n4, n5, n6, n7, n8, n9, n10, n11, and n12