-6*sqrt(7) cannot be simplified. Its value is -15.8745, approx.
97
98
The simplest radical form of the square root of 252 can be found by factoring it into its prime components. The prime factorization of 252 is (2^2 \times 3^2 \times 7). Therefore, (\sqrt{252} = \sqrt{2^2 \times 3^2 \times 7} = 2 \times 3 \times \sqrt{7} = 6\sqrt{7}). Thus, the simplest radical form is (6\sqrt{7}).
1.1667
It depends. Is the entire expression squared or just radical 7?Assuming the latter, then 6 + (√7)^2 = 6 + 7 = 13.
97
98
7 times the square root of 6
The simplest radical form of the square root of 252 can be found by factoring it into its prime components. The prime factorization of 252 is (2^2 \times 3^2 \times 7). Therefore, (\sqrt{252} = \sqrt{2^2 \times 3^2 \times 7} = 2 \times 3 \times \sqrt{7} = 6\sqrt{7}). Thus, the simplest radical form is (6\sqrt{7}).
6 times the square root of 7
1.1667
It is -sqrt(7).
7*sqrt(600) = 7*sqrt(100*6) = 7*sqrt(100)*sqrt(6) = 7*10*sqrt(6) = 70*sqrt(6)
It depends. Is the entire expression squared or just radical 7?Assuming the latter, then 6 + (√7)^2 = 6 + 7 = 13.
294 is an integer and there is no sensible radical form for it.
The square root of 504 can be simplified in radical form. First, we can factor 504 into its prime factors: (504 = 2^3 \times 3^2 \times 7). Taking the square root gives us (\sqrt{504} = \sqrt{(2^2 \times 3^2 \times 2 \times 7)} = 6\sqrt{14}). Thus, the square root of 504 in radical form is (6\sqrt{14}).
6√5 + 2√5 - 7 = 8√5 - 7, which cannot be simplified.