-6*sqrt(7) cannot be simplified. Its value is -15.8745, approx.
97
98
The simplest radical form of the square root of 252 can be found by factoring it into its prime components. The prime factorization of 252 is (2^2 \times 3^2 \times 7). Therefore, (\sqrt{252} = \sqrt{2^2 \times 3^2 \times 7} = 2 \times 3 \times \sqrt{7} = 6\sqrt{7}). Thus, the simplest radical form is (6\sqrt{7}).
The expression "the radical of 4 times the radical of 7" can be written mathematically as (\sqrt{4} \times \sqrt{7}). Since (\sqrt{4} = 2), the expression simplifies to (2 \times \sqrt{7}). Thus, the final answer is (2\sqrt{7}).
1.1667
97
98
The simplest radical form of the square root of 252 can be found by factoring it into its prime components. The prime factorization of 252 is (2^2 \times 3^2 \times 7). Therefore, (\sqrt{252} = \sqrt{2^2 \times 3^2 \times 7} = 2 \times 3 \times \sqrt{7} = 6\sqrt{7}). Thus, the simplest radical form is (6\sqrt{7}).
7 times the square root of 6
6 times the square root of 7
The expression "the radical of 4 times the radical of 7" can be written mathematically as (\sqrt{4} \times \sqrt{7}). Since (\sqrt{4} = 2), the expression simplifies to (2 \times \sqrt{7}). Thus, the final answer is (2\sqrt{7}).
1.1667
It is -sqrt(7).
7*sqrt(600) = 7*sqrt(100*6) = 7*sqrt(100)*sqrt(6) = 7*10*sqrt(6) = 70*sqrt(6)
It depends. Is the entire expression squared or just radical 7?Assuming the latter, then 6 + (√7)^2 = 6 + 7 = 13.
The square root of 504 can be simplified in radical form. First, we can factor 504 into its prime factors: (504 = 2^3 \times 3^2 \times 7). Taking the square root gives us (\sqrt{504} = \sqrt{(2^2 \times 3^2 \times 2 \times 7)} = 6\sqrt{14}). Thus, the square root of 504 in radical form is (6\sqrt{14}).
294 is an integer and there is no sensible radical form for it.