x2+2x-63 = 0 When factorised: (x-7)(x+9) = 0 Therefore: x = 7 or x = -9
x2 - 2x = 63 x2 - 2x - 63 = 0 Find two factors of -63 that add to -2 (including the sign). These are (-9,7) so, x2 - 9x + 7x - 63 = 0 x*(x-9) + 7*(x-9) = 0 (x-9)*(x+7) = 0 and so x - 9 or x = -7
x2-2x = 63 x2-2x -63 = 0 => x = -7 or x = 9 So x must = 9 Check: 92-18 = 63
Let x = length; then x + 2 = width which is next odd integer x (x+2) = 63 x^2 + 2x - 63 = 0 (X-7)(x+9) = 0 X = 7 = length; width = 9
63
xy=63 x +y = 16 y = 16-x x(16-x) = 63 16x -x^2 -63 = 0 x^2 -16x+63 = 0 (x-9)(x-7) = 0 x = 9 y = 7
47
x2+2x-63 = 0 When factorised: (x-7)(x+9) = 0 Therefore: x = 7 or x = -9
x2 - 2x = 63 x2 - 2x - 63 = 0 Find two factors of -63 that add to -2 (including the sign). These are (-9,7) so, x2 - 9x + 7x - 63 = 0 x*(x-9) + 7*(x-9) = 0 (x-9)*(x+7) = 0 and so x - 9 or x = -7
x2-2x = 63 x2-2x -63 = 0 => x = -7 or x = 9 So x must = 9 Check: 92-18 = 63
7x - 9y = -63.When y = 0 then the resultant answer provides the x intercept.7x - 0 = -63 : x = -9When x = 0 then the resultant answer provides the y intercept.0 - 9y = -63 : y = 7Alternatively, to ascertain the y intercept convert the equation into the form y = mx + c, c is the y intercept.7x - 9y = -63 : -9y = -7x -63 : 9y = 7x + 63 : y = 7/9x + 7
Let x = length; then x + 2 = width which is next odd integer x (x+2) = 63 x^2 + 2x - 63 = 0 (X-7)(x+9) = 0 X = 7 = length; width = 9
63
63 x 63 = 3969
The first ten positive integer multiples of 63 are as follows: 1 x 63 = 63 2 x 63 = 126 3 x 63 = 189 4 x 63 = 252 5 x 63 = 315 6 x 63 = 378 7 x 63 = 441 8 x 63 = 504 9 x 63 = 567 10 x 63 = 630
95
Sticking to integers: 7 x 9 = 63 3 x 21 = 63 1 x 63 = 63