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= 0.2709

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Q: 0.43 x 0 63
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What two whole numbers have a prooduct of 63 and a sum of 16?

xy=63 x +y = 16 y = 16-x x(16-x) = 63 16x -x^2 -63 = 0 x^2 -16x+63 = 0 (x-9)(x-7) = 0 x = 9 y = 7


What two numbers multiply to get 63 and add to get-16?

47


Can you solve x2 plus 2x - 63 equals 0?

x2+2x-63 = 0 When factorised: (x-7)(x+9) = 0 Therefore: x = 7 or x = -9


X squared minus two times x equals sixty-three?

x2 - 2x = 63 x2 - 2x - 63 = 0 Find two factors of -63 that add to -2 (including the sign). These are (-9,7) so, x2 - 9x + 7x - 63 = 0 x*(x-9) + 7*(x-9) = 0 (x-9)*(x+7) = 0 and so x - 9 or x = -7


What is the value of x when x squared - 2x is 63 showing your work in the form of an equation?

x2-2x = 63 x2-2x -63 = 0 => x = -7 or x = 9 So x must = 9 Check: 92-18 = 63


What is the intercepts 7x-9y equals -63?

7x - 9y = -63.When y = 0 then the resultant answer provides the x intercept.7x - 0 = -63 : x = -9When x = 0 then the resultant answer provides the y intercept.0 - 9y = -63 : y = 7Alternatively, to ascertain the y intercept convert the equation into the form y = mx + c, c is the y intercept.7x - 9y = -63 : -9y = -7x -63 : 9y = 7x + 63 : y = 7/9x + 7


The length and width of a rectangle are consecutive odd integers the area of the rectangle is 63 square units what is the length of the rectangle?

Let x = length; then x + 2 = width which is next odd integer x (x+2) = 63 x^2 + 2x - 63 = 0 (X-7)(x+9) = 0 X = 7 = length; width = 9


Factor x squared - 14x equals -49?

63


What is 63 x 63?

63 x 63 = 3969


What are the first ten multiples of 63?

The first ten positive integer multiples of 63 are as follows: 1 x 63 = 63 2 x 63 = 126 3 x 63 = 189 4 x 63 = 252 5 x 63 = 315 6 x 63 = 378 7 x 63 = 441 8 x 63 = 504 9 x 63 = 567 10 x 63 = 630


What two numbers that multiply to make 63 and add to make 32?

95


What can you multiply to get to 63?

Sticking to integers: 7 x 9 = 63 3 x 21 = 63 1 x 63 = 63