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Can you solve x2 plus 2x - 63 equals 0?
x2+2x-63 = 0 When factorised: (x-7)(x+9) = 0 Therefore: x = 7 or x = -9
X squared minus two times x equals sixty-three?
x2 - 2x = 63 x2 - 2x - 63 = 0 Find two factors of -63 that add to -2 (including the sign). These are (-9,7) so, x2 - 9x + 7x - 63 = 0 x*(x-9) + 7*(x-9) = 0 (x-9)*(x+7) = 0 and so x - 9 or x = -7
What is the value of x when x squared - 2x is 63 showing your work in the form of an equation?
x2-2x = 63 x2-2x -63 = 0 => x = -7 or x = 9 So x must = 9 Check: 92-18 = 63
The length and width of a rectangle are consecutive odd integers the area of the rectangle is 63 square units what is the length of the rectangle?
Let x = length; then x + 2 = width which is next odd integer x (x+2) = 63 x^2 + 2x - 63 = 0 (X-7)(x+9) = 0 X = 7 = length; width = 9
Factor x squared - 14x equals -49?
63
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