x2-2x = 63
x2-2x -63 = 0 => x = -7 or x = 9
So x must = 9
Check: 92-18 = 63
No, it is the discriminant of a quadratic equation.
No, not if the y is squared. When graphed the equation will not form a straight line.
To find the coefficient of the squared term in the parabola's equation, we can use the vertex form of a parabola, which is (y = a(x - h)^2 + k), where ((h, k)) is the vertex. Given the vertex at (3, 1), the equation starts as (y = a(x - 3)^2 + 1). Since the parabola passes through the point (4, 0), we can substitute these values into the equation: (0 = a(4 - 3)^2 + 1), resulting in (0 = a(1) + 1). Solving for (a), we find (a = -1). Thus, the coefficient of the squared term is (-1).
The equation ax2 + bx + c = 0, where a != 0 is called quadratic.
Because it is in the form of ax^2+bx+c=0 Because quadratic means squared hence ax squared + bx +c=0 has a squared number as it's highest term. This is in fact the area of a square of a side "x" is x^2, so every equation having variable with exponent 2 become quadratic equation.
No, it is the discriminant of a quadratic equation.
No, not if the y is squared. When graphed the equation will not form a straight line.
It is 22*54 = 2500.
To find the coefficient of the squared term in the parabola's equation, we can use the vertex form of a parabola, which is (y = a(x - h)^2 + k), where ((h, k)) is the vertex. Given the vertex at (3, 1), the equation starts as (y = a(x - 3)^2 + 1). Since the parabola passes through the point (4, 0), we can substitute these values into the equation: (0 = a(4 - 3)^2 + 1), resulting in (0 = a(1) + 1). Solving for (a), we find (a = -1). Thus, the coefficient of the squared term is (-1).
First, you remove every x that you can from the equation. Next, you reach the simplest form of the equation, which is (7x-2)(x-2). Which is the lowest factorable form.
The equation ax2 + bx + c = 0, where a != 0 is called quadratic.
Because it is in the form of ax^2+bx+c=0 Because quadratic means squared hence ax squared + bx +c=0 has a squared number as it's highest term. This is in fact the area of a square of a side "x" is x^2, so every equation having variable with exponent 2 become quadratic equation.
For a horizontal line, it is y= a value
In the equation y x-5 2 plus 16 the standard form of the equation is 13. You find the answer to this by finding the value of X.
expanded form
To find the coefficient of the squared term in the parabola's equation, we can use the vertex form of a parabola, which is (y = a(x - h)^2 + k), where ((h, k)) is the vertex. Here, the vertex is ((-3, -1)), so the equation becomes (y = a(x + 3)^2 - 1). Given that when (y = 0), (x = 4), we can substitute these values into the equation to find (a): [0 = a(4 + 3)^2 - 1 \implies 0 = a(7^2) - 1 \implies 1 = 49a \implies a = \frac{1}{49}.] Thus, the coefficient of the squared term is (\frac{1}{49}).
To isolate ( y^2 ) in the equation ( x^2 + 25y^2 = 100 ), first, subtract ( x^2 ) from both sides to get ( 25y^2 = 100 - x^2 ). Then, divide both sides by 25, resulting in ( y^2 = \frac{100 - x^2}{25} ). Thus, the equation in isolated form is ( y^2 = 4 - \frac{x^2}{25} ).