I'm assuming it looks like this:
0 > x + 5 > 5
so then the next step is to subtract 5 from every section.
-5 > x > 0
And there you go. :]
Wiki User
∙ 14y ago5*0 is 0
2
X is greater than 5. If X were equal to 5, X-5 would be 0 which has no real square root. If X were 4, X-5 would be -1 which has no real square root, and so on.
x is greater than or equal to 5.
2
x2-5x = 0 x(x-5) = 0 x = 0 or x = 5
what is c, x + 2y, x+y equal to or greater than 8, x equal to or greater than 3, y equal to or greater than 0.
X >= -5
5*0 is 0
2
X is greater than 5. If X were equal to 5, X-5 would be 0 which has no real square root. If X were 4, X-5 would be -1 which has no real square root, and so on.
x is greater than or equal to 5.
2
6 x 0 x 5 = 0 Because any number multiplied by 0 is equal to zero, 6 x 0 = 0 and then 0 x 5 = 0.
x > -5
(5, 0)
Split it into two cases. First - 6x-5 is positive(greater or equal to zero): Equation will get following form: 6x-5 <= 5 This resolves to x <= 10/6. Second case - 6x-5 is less than zero: Equation will get following form: -6x+5 <= 5 This resolves to x >= 0. As we can see, x has to be both greater than zero and less than or equal to 10/6, and this is our answer. 0 <= x <= 10/6