(5, 0)
I'm assuming it looks like this: 0 > x + 5 > 5 so then the next step is to subtract 5 from every section. -5 > x > 0 And there you go. :]
x2+11x+121 = x+96 x2+11x-x+121-96 = 0 x2+10x+25 = 0 Discriminant = b2-4ac = 102-4*1*25 = 0 The discriminant is equal to 0 so the quadratic equation will have two equal roots. (x+5)(x+5) = 0 Therefore: x = -5 and also x = -5 the answer is 0
i assume you mean what does x equal in this case. x = 0 here. x-5+9=4 x+4=4 x=0
If x^2 = 0, x = 0 Only 0^2 can equal 0.
x2-5x = 0 x(x-5) = 0 x = 0 or x = 5
6 x 0 x 5 = 0 Because any number multiplied by 0 is equal to zero, 6 x 0 = 0 and then 0 x 5 = 0.
(5, 0)
x+4x+5 = 0 5x + 5 = 0 5x = -5 x = -1
I'm assuming it looks like this: 0 > x + 5 > 5 so then the next step is to subtract 5 from every section. -5 > x > 0 And there you go. :]
0
x2+11x+121 = x+96 x2+11x-x+121-96 = 0 x2+10x+25 = 0 Discriminant = b2-4ac = 102-4*1*25 = 0 The discriminant is equal to 0 so the quadratic equation will have two equal roots. (x+5)(x+5) = 0 Therefore: x = -5 and also x = -5 the answer is 0
i assume you mean what does x equal in this case. x = 0 here. x-5+9=4 x+4=4 x=0
If x^2 = 0, x = 0 Only 0^2 can equal 0.
12
5 raised to the power 3 equals 5 x 5 x 5 = 125 a to the power of 3 equals a x a x a zero to the power 3 = 0 x 0 x 0 = 0 zero to the power 10 = 0 x 0 x 0 x 0 x 0 x 0 x 0 x 0 x 0 x 0 = 0 So you can see that no matter how many times we multiply zero by itself the answer is always zero. Hence zero raised to the power zero equals zero
y = x²-6x+5 is the equation. If it is factorized, you get (x-5)(x-1) We need y to equal zero, so either (x-5) or (x-1) can be zero (because 0 times anything equals 0). So, x-5 = 0 meaning that x=5 or x-1 = 0 meaning that x=1 Hope this helps!