There are very many possible solutions. The simplest polynomial solution is t(n) = (n^4 - 14n^3 + 71n^2 + 14n + 24)/24.
To find the 18th term of the arithmetic sequence 3, 10, 17, 24..., first, identify the common difference. The difference between consecutive terms is 7 (10 - 3, 17 - 10, 24 - 17). The formula for the nth term of an arithmetic sequence is given by ( a_n = a_1 + (n - 1)d ), where ( a_1 ) is the first term and ( d ) is the common difference. For the 18th term: ( a_{18} = 3 + (18 - 1) \times 7 = 3 + 119 = 122 ).
To find the nth term of the sequence 9, 12, 17, 24, 33, we first look at the differences between consecutive terms: 3, 5, 7, and 9. These differences themselves increase by 2, indicating a quadratic relationship. We can derive the nth term formula as ( a_n = n^2 + 8n + 1 ). Thus, the nth term of the sequence can be expressed as ( a_n = n^2 + 8n + 1 ).
To find the nth term of the sequence 9, 12, 17, 24, 33, 44, we first observe the differences between consecutive terms: 3, 5, 7, 9, 11. These differences form an arithmetic sequence with a common difference of 2. This suggests that the nth term can be expressed as a quadratic function. By deriving the formula, the nth term is given by ( a_n = n^2 + 8n - 1 ).
t(3) = 10 - 32 = 1
7n - 4
The nth term in the arithmetic progression 10, 17, 25, 31, 38... will be equal to 7n + 3.
The nth term is 7n-4 and so the next number in the sequence is 31
Subtract 7 from each number, so the 9th number would be 59.
You can see that all the numbers go up by 7. This means that the first part of the nth term rule for this sequence is 7n. Now, you have to find out how to get from 7 to 3, 14 to 10, 21 to 17 ... this is because we are going up in the 7 times table. To get from the seventh times table to the sequence, you take away four. So the answer is : 7n-4
There are very many possible solutions. The simplest polynomial solution is t(n) = (n^4 - 14n^3 + 71n^2 + 14n + 24)/24.
To find the 18th term of the arithmetic sequence 3, 10, 17, 24..., first, identify the common difference. The difference between consecutive terms is 7 (10 - 3, 17 - 10, 24 - 17). The formula for the nth term of an arithmetic sequence is given by ( a_n = a_1 + (n - 1)d ), where ( a_1 ) is the first term and ( d ) is the common difference. For the 18th term: ( a_{18} = 3 + (18 - 1) \times 7 = 3 + 119 = 122 ).
The differnace between the numbr is 7, therefore the first part of the formula will be 7n, now for the first term we replace n with one so nx7=7 and to get to 10 you need to add 3 making the nth term 7n+3, To check your answer you must replace n with the two (for the second term) which comes to 14 to get to seventeen you need to add three so the formula nth term 7n+3, hope this helped
To find the nth term of the sequence 9, 12, 17, 24, 33, we first look at the differences between consecutive terms: 3, 5, 7, and 9. These differences themselves increase by 2, indicating a quadratic relationship. We can derive the nth term formula as ( a_n = n^2 + 8n + 1 ). Thus, the nth term of the sequence can be expressed as ( a_n = n^2 + 8n + 1 ).
To find the nth term of the sequence 9, 12, 17, 24, 33, 44, we first observe the differences between consecutive terms: 3, 5, 7, 9, 11. These differences form an arithmetic sequence with a common difference of 2. This suggests that the nth term can be expressed as a quadratic function. By deriving the formula, the nth term is given by ( a_n = n^2 + 8n - 1 ).
The nth term is 5n-3 and so the next term will be 22
5n - 3