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Apply Pythagoras.

d^2 = (-6--3)^2 + ( 0 - 1)^2

d^2 = ( -3)^2 + ( -1)^(2)

d^2 = 9 + 1

d^2 = 10

d = sqrt(10) = 3.1622....

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lenpollock

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βˆ™ 10mo ago
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βˆ™ 13y ago

(distance)2 = (difference in 'x' values)2 + (difference in 'y' values)2 = (3)2 + (1)2 = 10

Distance = sqrt(10) = 3.1623 (rounded)

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