-6
If a=b and c=d then (a+c)=(b+d) ? This is proved very simply by the direct application of perhaps the most fundamental statement in all of Algebra: "If equals are added to equals, the sums are equal."
4
13 is a bakers's dozen.
(a-d)/2c=b
As A/B=C/D , So B=(A*D)/C
They all equal each other. a = b = c = d = e e = a e = b e = c e = d e = e
the answer is a
-6
A plus b plus c equals d. A is the largest answer b is the smallest answer and d is less than 6?''
If a=b and c=d then (a+c)=(b+d) ? This is proved very simply by the direct application of perhaps the most fundamental statement in all of Algebra: "If equals are added to equals, the sums are equal."
If: a = b+c+d Then: c = a-b-d
a=3 b=5 c=1 D=b2-4ac D=25-12 D=13 x=-b +- Underoot of D The whole divided by 2a. x=-5+-Under root of 13 Divided by 6
4
The product of the means equals the product of the extremes. In other words, if A is to B as C is to D, then B times C equals A times D, so... A = B x C ÷ D B = A x D ÷ C C = A x D ÷ B D = B x C ÷ A
In the equation ABC x C = DBC, we can break down the multiplication as follows: (100A + 10B + C) x C = 100D + 10B + C. Simplifying, we get C x C = D, which implies that C must be either 1 or 5 (as the result of multiplying a single digit by itself cannot be a two-digit number). By trying out both values, we find that C = 5, A = 2, B = 4, and D = 2 to satisfy the equation.
13 is a Bakers Dozen.