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4x - 8 = 0 when x = 2

Substitute this value of x in 16x3 + 4x2 - 144 to give

16*8 + 4*4 - 144 = 128 + 16 - 144 = 144 - 144 = 0

So, by the remainder theorem, (x-2) is a factor of 16x3 + 4x2 - 144

Also, the coeffs are all divisibl by 4 so 4 is also a factor

(x-2) is a factor, 4 is a factor so 4*(x-2) = (4x - 8) is a factor.

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15y ago

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