(2x - 1)(6x + 5)
x=5
If you mean -12x+3y = 15 then y = 4x+5
y = 5 - 2x so 4x + 6(5 - 2x) = -2 ie 4x + 30 - 12x = -2 Subtract 30 from each side: 4x - 12x = -32 ie -8x = -32 so x = 4 and y = -3
Are you trying to find x? If so, get all x's to one side, 32=8x-8, then get x alone... 40= 8x then divide by 8... 5=x So at x=5, 4x+32=12x-8
5/4x+7/12x is the same as 15/12x+7/12x = 21/12x
(2x - 1)(6x + 5)
x=5
4x² - 12x + 9 = 5 → 4x² - 12x + 4 = 0 → x² - 3x + 1 = 0 → x = (-(-3) ±√((-3)² - 4×1×1))/(2×1) → x = (3 ±√5)/2 → x = (3 + √5)/2 or x = (3 - √5)/2
If you mean -12x+3y = 15 then y = 4x+5
The factors of 5 are 1 and 5. 12 = 2 x 5 + 2 x 1, therefore: 4x2 +12x +5 = (2x + 1)(2x + 5)
3x-8+5x+39+4x+51 = x(3+5+4) + -8 + 39 + 51 = 12x +82
y = 5 - 2x so 4x + 6(5 - 2x) = -2 ie 4x + 30 - 12x = -2 Subtract 30 from each side: 4x - 12x = -32 ie -8x = -32 so x = 4 and y = -3
Are you trying to find x? If so, get all x's to one side, 32=8x-8, then get x alone... 40= 8x then divide by 8... 5=x So at x=5, 4x+32=12x-8
-3
24x^3 + 72x2 + 30x = 6x*(4x^2 + 12x + 5)=6x*(2x + 1)*(2x + 5)
-8X + 7 = 4X - 5 add -8X to both sides 7 = 12X - 5 add 5 to each side 12 = 12X divide each side by 12 1 = X check -8(1) + 7 = 4(1) - 5 -1 = -1 checks