Well, we can see that all multiples of 3 have been removed.
Because we know that 149 is the final value, 147 is the final value that has been removed.
147/3=49, therefore we know that 49 values have been removed from the consecutive sequence of integers (1,2,3,4,5,6,7 etc.)
So, 149-49=100
Therefore there are 100 terms in the sequence.
149 + 10 = 159
Ignoring the "9" , then this is a Fibonacci sequence. 2,2,4,6,10 The first two terms are 'seed' terms then successive terms equal the sum of the two previous terms. 2 + 2 = 4 2 + 4 = 6 4 + 6 = 10 The next term would be 6 + 10 = 16.
no clue
9, 10, 11 and 12
Consecutive terms in the sequence are found by dividing by 2 and adding 2. Therefore, after the number 10 comes 10/2 + 2 = 7.
149 + 10 = 159
They are: 10 and 16
Ignoring the "9" , then this is a Fibonacci sequence. 2,2,4,6,10 The first two terms are 'seed' terms then successive terms equal the sum of the two previous terms. 2 + 2 = 4 2 + 4 = 6 4 + 6 = 10 The next term would be 6 + 10 = 16.
sequence 4 5 6 sum =10 sequecnce 0 5 10 sum=10
no clue
149/10 = 14.9
9, 10, 11 and 12
Consecutive terms in the sequence are found by dividing by 2 and adding 2. Therefore, after the number 10 comes 10/2 + 2 = 7.
20, 15, 10, 5, 0, -5, -10, -15, -20 and so on.
Double it every time and so the next number will be 80
10% off 149 = 149 - 14.9 = 134.1
There are 10 millimetres in one centimetre. Therefore, 149 millimetres is equal to 149/10 = 14.9 centimetres.