20, 15, 10, 5, 0, -5, -10, -15, -20 and so on.
5
4,8,12,16,20
sequence 4 5 6 sum =10 sequecnce 0 5 10 sum=10
2
5, 11, 17, 23, 29
37
To find the first three terms of an arithmetic sequence with a common difference of -5, we first need the last term. If we denote the last term as ( L ), the terms can be expressed as ( L + 10 ), ( L + 5 ), and ( L ) for the first three terms, since each term is derived by adding the common difference (-5) to the previous term. Thus, the first three terms would be ( L + 10 ), ( L + 5 ), and ( L ).
5
it is 8.
4,8,12,16,20
sequence 4 5 6 sum =10 sequecnce 0 5 10 sum=10
2
5, 11, 17, 23, 29
a1=2 d=3 an=a1+(n-1)d i.e. 2,5,8,11,14,17....
They are 14, 42, 126, 378 and 1134.
Double it every time and so the next number will be 80
10, 8, 6, 4, 2, 0, -2, -4