2,1,0 is th sequence of its terms
3925
2n+4/2 term 1 = 3 term 2 = 4 term 3 = 5 term 4 = 6
n = 1 ---> 3 * 1 + 3 = 6 n = 2 ---> 3 * 2 + 3 = 9 first 2 have difference of 3, so you can keep adding 3 to find more terms. 6, 9, 12, 15
No. It is a sum of four terms which can be simplified to a sum of three terms.
2,1,0 is th sequence of its terms
3925
2n+4/2 term 1 = 3 term 2 = 4 term 3 = 5 term 4 = 6
9, 17, 25, 33, 41
n = 1 ---> 3 * 1 + 3 = 6 n = 2 ---> 3 * 2 + 3 = 9 first 2 have difference of 3, so you can keep adding 3 to find more terms. 6, 9, 12, 15
No. It is a sum of four terms which can be simplified to a sum of three terms.
5, 8, 11, 14 and 17.
12+7=8, 22+7=11, 32+7=16, 42+7=23
Starting from 1, your get: [4n + 5] = 9, 13, 17, 21, 25 Basically you find the first one and add 4 each time.
They are four terms of an algebraic expression that can't be simplified
A(1) = 12A(4) = 3 A(10) = -15.
They are four terms of an expression that can be simplified to: 16+h