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How do you represent root 2 to root 9 in the number line?
By root, I think you mean square root. The square root of 2 is approx. 1.414. The square root of 9 = 3, so this goes exactly at 3 on the number line. Square root 2 will be less than 1/2 way between 1 and 2 on the number line.
If 1 plus 2 equals 3 than what is 9999999999999999999999's square root?
The exact square root of 9999999999999999999999 is 33 times the square root of 9182736455463728191.
X2-6x plus 1 equals 0?
x2 - 6x + 1 = 0 x = [-(-6) +&- square root of [(-6)2 - 4(1)(1)]]/2(1) x = (6 +&- square root of 32)/2 x = [6 +&- 4(square root of 2)]/2 x = 3 +&- 2(square root of 2) x = 3 + 2(square root of 2) or x = 3 - 2(square root of 2) Check:
Is 1.1 bigger than the square root of 2?
No because square root of 2 is bigger
What is the answer to 1 divided by 2 times the square root of 2?
wow u cant figure out awnser relly the At first you will multiply the, (1 divided by 2 square root of 2) by (2square root of 2 divided by 2 square root of 2) because 2 square root of 2 is irrational. so the answer is square root of 2 over 4.
