2x-y+4=0... what are you actually trying to find?
2xy - 4x plus 8y - 16 equals x plus 4 in parentheses multiplied by 2y minus 4 in parentheses. So, the factors are ( x + 4) and ( 2y - 4) .
1 plus 1 plus 1 plus 1 equals 1 times 4. 1 times 4 equals 4. 4 minus 4 equals 0. 0
22 = 4
x = y = 0 ?
To solve the expression -3 plus -1 plus 0 plus 1 plus 3, we can combine the numbers step by step. First, -3 plus -1 equals -4. Then, adding 0 does not change the value, so we still have -4. Next, -4 plus 1 equals -3, and finally, -3 plus 3 equals 0. Therefore, the final result is 0.
2xy - 4x plus 8y - 16 equals x plus 4 in parentheses multiplied by 2y minus 4 in parentheses. So, the factors are ( x + 4) and ( 2y - 4) .
1 plus 1 plus 1 plus 1 equals 1 times 4. 1 times 4 equals 4. 4 minus 4 equals 0. 0
Assuming y' is dy/dx, y = x^4/4 + yx^2
22 = 4
x = y = 0 ?
the difference between 2x2 +4xy-3 and x2-2xy-4 is?
To solve the expression -3 plus -1 plus 0 plus 1 plus 3, we can combine the numbers step by step. First, -3 plus -1 equals -4. Then, adding 0 does not change the value, so we still have -4. Next, -4 plus 1 equals -3, and finally, -3 plus 3 equals 0. Therefore, the final result is 0.
(2xy-4x)+ (8y-16)=2xy-4x+8y-16, which factors as 2(x+4)(y-2)
4(x + 1) = 0.
4xy - 2y(x + 4) = 4xy - 2xy - 8y = 2xy - 8y = 2y(x - 4)
That would still be 4. If it were times 0 it would be 0.
x = 0