I'm assuming you want to solve the equation
2x2 - 12x - 80 = 0
Divide both sides by 2:
x2 - 6x - 40 =0
What numbers multiply to get -40 and add to give you -6?
Factors of 40:
(2,20)
(4,10)
(5,8)
Thus, the factors of -40 are the same, but with either number in the pair being negative. Which two have a difference of 6? (4,10). Since we want -6, we should choose (4,-10)
Thus we can factor the equation to get:
(x + 4)(x - 10) = 0
The two solutions are then x= -4, x=10
Yes. You must use the "slip and slide" factoring method because there is a 2 coefficient infront of x2. 2x2-12x-80 = (x-10)(2x+8)
2(x + 4)(x - 10)
Do you want its factorisation? 2x3 + 2x2 - 12x = 2x(x2 + x - 6) = 2x(x + 3)(x - 2).
(-2x3 - 2x2 + 12x) = -2x (x2 + x - 6) = -2x (x + 3) (x - 2)
Yes because dividing all terms by 2 it becomes x2-6x-40 = (x-10)(x+4) when factored
Yes. You must use the "slip and slide" factoring method because there is a 2 coefficient infront of x2. 2x2-12x-80 = (x-10)(2x+8)
2(x + 4)(x - 10)
Do you want its factorisation? 2x3 + 2x2 - 12x = 2x(x2 + x - 6) = 2x(x + 3)(x - 2).
whats the answer for -2x^3+2^2+12x
-2x3 + 2x2 + 12x =(-2x) (x2 - x - 6) =(-2x) (x+2) (x-3)
I assume your problem is: -2x3-2x2+12x-2x(x2-x-6)-2x(x-3)(x+2)
(-2x3 - 2x2 + 12x) = -2x (x2 + x - 6) = -2x (x + 3) (x - 2)
2x2 - 72 would be factored into (2x - 12)(x + 6) or (2x + 12)(x - 6) To double check, multiply each pair: (2x - 12)(x + 6) = 2x2 + 12x - 12x - 72 = 2x2 - 72 (2x + 12)(x - 6) = 2x2 - 12x + 12 x - 72 = 2x2 - 72
Yes because dividing all terms by 2 it becomes x2-6x-40 = (x-10)(x+4) when factored
2*2 - 12x +16 =0 4 - 12x +16 =0 -12x + 16 +4 =0 -12x + 20 =0 -12x = -20 x = 1.666666667
2x2 + 6 = 30 is your statement.2x2 = 24x2 = 12x = ±√12x = ±√(4*3)x = 2√3 or x = -2√3
There is no rational factorisation to this expression.