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I'm assuming you want to solve the equation

2x2 - 12x - 80 = 0

Divide both sides by 2:

x2 - 6x - 40 =0

What numbers multiply to get -40 and add to give you -6?

Factors of 40:

(2,20)

(4,10)

(5,8)

Thus, the factors of -40 are the same, but with either number in the pair being negative. Which two have a difference of 6? (4,10). Since we want -6, we should choose (4,-10)

Thus we can factor the equation to get:

(x + 4)(x - 10) = 0

The two solutions are then x= -4, x=10

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Q: 2x2 - 12x - 80
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