x3 + 2x2 + 3x + 6 = x2(x + 2) + 3(x + 2) = (x + 2)(x2 + 3)
2x( x2 + x - 6) = 2x (x + 3)(x - 2)
2(x^2 +2x + 3)
x + 2x2 = 6 is the equation but if you wanted to solve it... 2x2 + x - 6 = 0 [FACTOR] (2x + 3) (x - 2) = 0 [Set it equal to zero] x = 2 or -3/2 [answer]
You would factor 2x2 + 7x + 6 into (2x + 3) (x+2)
2(x - 6)(x + 6)
(2x+3)(x-2)
2(x + 3)(x + 1)
-((2x + 7)(x - 6))
2x2-4x-3x+6 2x2-7x+6 (2x+3)(x+2)
2(x + 6)(x + 3)
2x2 - 72 would be factored into (2x - 12)(x + 6) or (2x + 12)(x - 6) To double check, multiply each pair: (2x - 12)(x + 6) = 2x2 + 12x - 12x - 72 = 2x2 - 72 (2x + 12)(x - 6) = 2x2 - 12x + 12 x - 72 = 2x2 - 72
2x2 + 7x + 6 = 2x2 + 4x + 3x + 6 = 2x(x + 2) + 3(x + 2) = (x + 2)(2x + 3)
x3 + 2x2 + 3x + 6 = x2(x + 2) + 3(x + 2) = (x + 2)(x2 + 3)
4x2 - 2x - 12= 2x2 - x - 6= 2x2 - 4x + 3x - 6= 2x(x - 2) + 3(x - 2)= (x - 2)(2x + 3)
2x( x2 + x - 6) = 2x (x + 3)(x - 2)
2(x^2 +2x + 3)