2x2 + 7x + 3 = (2x + 1)(x + 3)
If 2x2 + 7x + 3 = 0 then:
(2x + 1)(x + 3) = 0
⇒ (2x + 1) = 0 → x = -1/2
or (x + 3) = 0 → x = - 3
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(2x + 1)(x + 3)
x2 + 7x = 2x2 + 6 x2 - 2x2 + 7x = 6 -x2 +7x - 6 = 0 or alternatively x2 - 7x + 6 = 0
You would factor 2x2 + 7x + 6 into (2x + 3) (x+2)
(2x + 1)(x + 3) = 0; x = -0.5 or -3
(2x + 1) (x + 3) = 2x2 + 7x + 3