this can not be solved un less with another equation
2x + 3y = 9x = 3, y = 1 therefore 6 + 3 = 9
Yes and it works out that x = 3 and y = 4
2x-11
-2x plus 3y equals 1
To solve the equation (2x + 3y = 12) for (x), first, isolate (2x) by subtracting (3y) from both sides, giving (2x = 12 - 3y). Then, divide both sides by 2 to solve for (x): (x = \frac{12 - 3y}{2}). Simplifying further, (x = 6 - \frac{3y}{2}).
(3,3)
2x + 3y = 9x = 3, y = 1 therefore 6 + 3 = 9
Yes and it works out that x = 3 and y = 4
2x-11
-2x plus 3y equals 1
To solve the equation (2x + 3y = 12) for (x), first, isolate (2x) by subtracting (3y) from both sides, giving (2x = 12 - 3y). Then, divide both sides by 2 to solve for (x): (x = \frac{12 - 3y}{2}). Simplifying further, (x = 6 - \frac{3y}{2}).
(2,7)
2x plus 3y
2x + 3y = 17 3x + 4y = 24 (2x + 3x) + (3y + 4y) = (17 + 24) 5x + 7y = 41
x + y = -2 2x + 3y = -9 You solve this by elimination - multiply both sides of first equation by 3, then subtract, solve for x, then substitute in any of the equations to solve for y 3x + 3y = -6 2x + 3y = -9 subtracting, x = 3 substituting into 1st equation, y = -2-3 = -5
2x-3y=13
y=16 x= -4