If you mean -2x+y = 8 then y = 2x+8 as a straight line equation
The variable 'x' would equal (8-y)/2. The variable 'y' would equal 8-2x.
2x+4y = -8 4y = -2x-8 y = -1/2x-2 or y = -0.5x-2
Y = 2X + 8 is a linear function of the form, Y = mX + c. A line.
The domain and range of the equation y = 2x+8 are both [-infinity,+infinity].
xy plus 2x plus 4y plus 8 or (xy+2x) + (4y+8) or x(y+2) + 4(y+2) or (x+4)(y+2)
y=6x-16 y=-2x+8
If you mean -2x+y = 8 then y = 2x+8 as a straight line equation
The variable 'x' would equal (8-y)/2. The variable 'y' would equal 8-2x.
x + y = 10 y = x + 8 so, x + (x + 8) = 10 2x + 8 = 10 2x + 8 - 8 = 10 - 8 2x = 2 x = 1 and y = 9 because y = x + 8 y = 1 + 8 y = 9
2x+4y = -8 4y = -2x-8 y = -1/2x-2 or y = -0.5x-2
Y = 2X + 8 is a linear function of the form, Y = mX + c. A line.
4
x + y = 10 y = x + 8 so, x + (x + 8) = 10 2x + 8 = 10 2x + 8 - 8 = 10 - 8 2x = 2 x = 1 and y = 9 because y = x + 8 y = 1 + 8 y = 9
8
The domain and range of the equation y = 2x+8 are both [-infinity,+infinity].
2x+y = 8 y = -x+5 Substitute y for -x+5 into the first equation: 2x+(-x+5) = 8 2x-x+5 = 8 x = 8-5 x = 3 Substitute the value of x into the original equations to find the value of y: x = 3 and y = 2