Q: 32 T IN AN A H H?

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0.666 ^^^^ his answer mine 3 in 8 i believe. which is 0.375 you can get h,h,h h,t,h h,t,t h,h,t t,h,h t,t,h t,h,t t,t,t the ones you are looking for are h,h,t t,h,h h,t,h

There are 8 permutations of three coins ... T T T T T H T H T T H H H T T H T H H H T H H H ... counting heads and sorting by count, you get ... 0 - T T T 1 - T T H 1 - T H T 1 - H T T 2 - T H H 2 - H T H 2 - H H T 3 - H H H ... so, the probability of each possible number of heads is 0: 1 in 8, 1: 3 in 8, 2: 3 in 8, and 3: 1 in 8.

4 : Each coin toss multiplies the generated outcome by two. The outcome for two tosses can be Heads (H) Tails (T), H H, T T or T H. As such, with three tosses the outcome can be H H H, H H T, H T H, T H H, T T H, T T T, T H T, H T T. We can define the number of outcomes as 2^n, where n is the amount of tosses.

The height, in feet, above the ground at time t, H(t) = 40 + 32*t - 16*t2

4: h/h, h/t, t/h & t/t

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32 t in the h m

Each flip can land in 2 ways. Total number of possible ways that 5 flips can land is2 x 2 x 2 x 2 x 2 = 32 different ways.There are only 5 different ways to get exactly 3 heads in a row in 5 flips.They are:H H H T TH H H T HT H H H TT T H H HH T H H H.The probabilty is 5/32 = 15.625 percent.====================================================That's if you mean exactly 3 heads in a row ... no less and no more.What if you asked for "at least 3 heads in a row" ?There are 8 ways to do that:The original five ways to get 3 in a row . . .H H H T TH H H T HT H H H TT T H H HH T H H HPlus 2 ways to get 4 in a row . . .T H H H HH H H H TPlus a way to get 5 in a row . . .H H H H H.The probability of one of these outcomes is 8/32 = 25 percent.

1 2 3 4 h h h h h h h t h h t h h h t t h t h h h t h t h t t h h t t t t h h h t h h t t h t h t h t t t t h h t t h t t t t h t t t t

4 coins tossed could have the following patterns T T T T T T T H, T T H T, T H T T, H T T T T T H H, T H T H, T H H T, H H T T, H T H T, H T T H H H H T, H H T H, H T H H, T H H H H H H H Odds of 2H&2T = 6/16 = .375

nobody because they thought it was a piece of S S S S S S S S S S S S S S S S S S S S S S S S S S S S S S S S S S S S S S S S H H H H H H H H H H H H H H H H H H H H H H H H H H H H H H H H H H H H I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T

8: h-h-h, h-h-t, h-t-h, t-h-h, t-t-h, t-h-t, h-t-t and t-t-t.

0.666 ^^^^ his answer mine 3 in 8 i believe. which is 0.375 you can get h,h,h h,t,h h,t,t h,h,t t,h,h t,t,h t,h,t t,t,t the ones you are looking for are h,h,t t,h,h h,t,h

32 teeth in a human mouth Although this only applies to an adult human with all four wisdom teeth.

There are 8 permutations of three coins ... T T T T T H T H T T H H H T T H T H H H T H H H ... counting heads and sorting by count, you get ... 0 - T T T 1 - T T H 1 - T H T 1 - H T T 2 - T H H 2 - H T H 2 - H H T 3 - H H H ... so, the probability of each possible number of heads is 0: 1 in 8, 1: 3 in 8, 2: 3 in 8, and 3: 1 in 8.

4 : Each coin toss multiplies the generated outcome by two. The outcome for two tosses can be Heads (H) Tails (T), H H, T T or T H. As such, with three tosses the outcome can be H H H, H H T, H T H, T H H, T T H, T T T, T H T, H T T. We can define the number of outcomes as 2^n, where n is the amount of tosses.

If the 'outcome' means heads vs. tails, then there are 8 possibilities. They are: 1). H H H 2). H H T 3). H T H 4). H T T 5). T H H 6). T H T 7). T T H 8). T T T

The height, in feet, above the ground at time t, H(t) = 40 + 32*t - 16*t2