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2*(32/6) = 2*(31/3) = 2*10/3 = 20/3 = 62/3

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Q: 3 and 2 out of 6 doubled?
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How could you keep an object acceleration the same if the force acting on object were doubled?

force = mass * acceleration if force is doubled, mass needs to be doubled to keep the same acceleration example: force = 6 mass = 2 acceleration = 3 6 = 2 * 3 12 = m * 3 12/3 = m 4 = mass


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