a+b+c=267
simplify to one var
x+(x+1)+(x+2)=267
x+x+1+x+2=267
3x+3=267
3x+3-3=267-3
3x=264
3x/3=264/3
x=88
therefore
a=88
b=89
c=90
87,89,91.....87+89+91=267
3 consecutive even integers whose sum is 396 are 130, 132 and 134.
The sum of three consecutive integers starting with ( n ) can be expressed as ( n + (n + 1) + (n + 2) ). Simplifying this expression gives ( 3n + 3 ). Therefore, the sum of the three consecutive integers is ( 3n + 3 ) or ( 3(n + 1) ).
24 + 25 + 26 = 75
The numbers are 23, 24 and 25.
88,89,90 the answer is 88, 89,90.
x + (x+1) + (x + 2) = 267 3x + 3 = 267 3x = 264 x = 88 Answer: 88, 89, 90
It need not be. 2 and 3 are consecutive integers and their sum is 5, not 31.
87,89,91.....87+89+91=267
Divide the sum of the three consecutive odd integers by 3: -3 /3 = -1. The smallest of these integers will be two less than -1 and the largest will be two more than -1, so the three consecutive odd integers will be -3, -1, and +1.
201
They are are 62, 63 and 64.
3 consecutive even integers whose sum is 396 are 130, 132 and 134.
The sum of even integers cannot end with 9. why not
The sum of three consecutive integers starting with ( n ) can be expressed as ( n + (n + 1) + (n + 2) ). Simplifying this expression gives ( 3n + 3 ). Therefore, the sum of the three consecutive integers is ( 3n + 3 ) or ( 3(n + 1) ).
-3,-4,-5
The integers are 24, 25 and 26.