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xxx-2xx-15xx(xx-2x-15)Factor (long):axx+bx+ca=1b=-2c=-15Multiply a and c:1*-15=-15Find multiples of ac that add up to b (d,e [ie de=ac, d+e=b]):-15=-1*3*5-15=3*-5, -3*5Rewrite axx+bx+c into axx+dx+ex+c:x(xx+3x-5x-15)Factor sets of terms (ie axx+dx, and ex+c):x(xx+3x-5x-15)x(x(x+3)-5(x+3))Combine like terms:x(x-5)(x+3)Factor (short):-if trinomial is written in the form of 1xx+bx+c it can be written in the form of (x+d)(x+e) where d and e are multiples of c that add up to bx(xx-2x-15)Multiply a and c:1*-15=-15Find multiples of ac that add up to b (d,e [ie de=ac, d+e=b]):-15=-1*3*5-15=3*-5, -3*5x(x+3)(x-5)
d/3+3 = 5 d+9 = 15 d = 15-9 d = 6
The answer would depend on a 3-dimensional WHAT! It is not a 3-d circle, for example.The answer would depend on a 3-dimensional WHAT! It is not a 3-d circle, for example.The answer would depend on a 3-dimensional WHAT! It is not a 3-d circle, for example.The answer would depend on a 3-dimensional WHAT! It is not a 3-d circle, for example.
is 10*abs(d-3) or 10*|d-3| where abs is the absolute difference between d and 3 ie it is always the positive value.
If: df+10f = 3 Then: f(d+10) = 3 And: d = 3/f -10