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In Dungeons & Dragons (D&D), Armor Class (AC) represents how difficult it is to hit a character with an attack. AC is typically calculated using a character's base AC, which is determined by their armor type, plus any modifiers from Dexterity, magical items, or spells. For example, a character wearing chain mail has a base AC of 16, while a character wearing leather armor might add their Dexterity modifier to a base of 11. Additionally, certain abilities and spells can further modify a character's AC.

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3 d in an ac?

Three digits in an area code.


Why do denominators change as you simplify the fraction?

I use the rule that: (a/b)x(c/d)=(ab/cd) and (a/b)divided by(c/d)= (ac/bd) The reason they change is that when you have to find the lowest common factor, you not only have to change the denominator, but also the numerator.


If BC 7 and CD 24 find AC.?

To find AC, you need to add the lengths of segments BC and CD together. If BC is 7 and CD is 24, then AC = BC + CD = 7 + 24 = 31. Therefore, AC is 31 units long.


Write a program using switch case to find the area of a square rectangle and a cylinder using functions?

# include # include int ch,r,a,h,d,l; float Ac, Ar, At; void main() { clrscr(); printf("\n press1,area of circle"); printf("\n press2,area of rectangle"); printf("\n press3,area of triangle"); printf("\n enter your choice"); scanf("%d",&ch); switch(ch) { case 1: printf("\n enter values to find area of circle"); scanf ("%d",&r); Ac = 3.14*r*r; printf("\n area of circle is %f",Ac); break; case 2: printf("\n enter values to find area of rectangle "); scanf("%d%d",&a,&h); Ar= a*h; printf("\n area of rectangle is %f",Ar); break; case 3: printf("\n enter values to find volume of cylinder"); scanf("%d%d",&d,&l); At = 0.5*d*l; printf("\n area of triangle is %f",At); break; DEFAULT: printf("\n enter the proper choice"); } getch(); }


What is the formula to find AC?

To find the length of side AC in a triangle, you can use the Law of Cosines if you know the lengths of the other two sides (AB and BC) and the included angle (∠B). The formula is: [ AC^2 = AB^2 + BC^2 - 2 \times AB \times BC \times \cos(\angle B) ] After calculating AC², take the square root to find AC. If you have a right triangle, you can simply use the Pythagorean theorem: [ AC = \sqrt{AB^2 + BC^2} ] (assuming AC is the hypotenuse).

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