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3 numbers whose product is about 9000?
Prime factorisation of 9000 = 2*2*2*3*3*5*5*5 Well 9000 can be expressed as the product of (2*2*2)*(3*3)*(5*5*5) or 8*9*125 So, 9000 can be expressed as the product of 8,9 and 125. It can be expressed as 2*(2*2*5*5)*(3*3*5) i.e. 9000 = 2*100*45 By using the method of Prime factorisation, we can find many cases in which product of 3 numbers is 9000. We can also express it as 900*(1/10)*100, which cannot be done using P.F. of 9000. We can find a large number of cases in which product of three numbers is 9000. We can find numbers by this method: Assume any three variables and put their product equal to 9000 i.e. x*y*z = 9000 where x,y and z are real numbers. Put any value of x, say 34 and any value of y, say 23, then on putting the values we can find the value of z i.e. 34*23*z = 9000 782*z = 9000 z = 11.5089 So, this method works better than Prime Factorisation.
What 3 numbers whose product is -36 and whose sum is 5?
The three numbers are 2, -3, and 6.
What two numbers whose product is 48 and whose sum is -19?
67
What are two numbers whose product is 33 and whose sum is 14?
3 and 11.
What are two numbers whose product is 90?
30 and 3
3 numbers whose product is about 9000 estimate?
As a product of its prime factors in exponents: 23*32*53 = 9000
What are Three numbers whose product is about 9000 using multiplication?
3 x 3 x 1000
What 3 numbers make the product of 9000?
20.800838230519041145300568243579 * 20.800838230519041145300568243579 * 20.800838230519041145300568243579 = 9000
3 numbers that product is about 9000?
(2) x (3) x (1,500.1) will do it.
3 numbers whose product is about 9000?
Prime factorisation of 9000 = 2*2*2*3*3*5*5*5 Well 9000 can be expressed as the product of (2*2*2)*(3*3)*(5*5*5) or 8*9*125 So, 9000 can be expressed as the product of 8,9 and 125. It can be expressed as 2*(2*2*5*5)*(3*3*5) i.e. 9000 = 2*100*45 By using the method of Prime factorisation, we can find many cases in which product of 3 numbers is 9000. We can also express it as 900*(1/10)*100, which cannot be done using P.F. of 9000. We can find a large number of cases in which product of three numbers is 9000. We can find numbers by this method: Assume any three variables and put their product equal to 9000 i.e. x*y*z = 9000 where x,y and z are real numbers. Put any value of x, say 34 and any value of y, say 23, then on putting the values we can find the value of z i.e. 34*23*z = 9000 782*z = 9000 z = 11.5089 So, this method works better than Prime Factorisation.
What are the two prime numbers whose product is 141?
two prime numbers whose product is 141 = 3 & 47
What are the only 2 prime numbers whose product is 21?
3 and 7 are prime numbers whose product is 21.
What 3 numbers whose product is -36 and whose sum is 5?
The three numbers are 2, -3, and 6.
What two numbers whose product is 48 and whose sum is -19?
67
What two numbers whose product is negative 18 and whose sum is 3?
6 and -3.
What is the product of two prime numbers whose sum is twenty?
17 and 3 are two prime numbers whose sum is 20. Their product is 51.
What are two numbers whose product is 33 and whose sum is 14?
3 and 11.
