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2x + 5y = 2

-3x - y = -3

from the second equation:

-y = -3 + 3x

y = 3 - 3x

substitute this value in the first equation:

2x + 5(3-3x) = 2

2x + 15 - 15x = 2

-13x + 15 = 2

-13x = 2 - 15

-13x = -13

so, x = 1

Now, solve for y :

y = 3 - 3x

y = 3 - 3 (1)

y = zero

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