Do you mean: 3x2-17x+10? If so then it is: (3x-2)(x-5)
(x+1)(x+5)(x+2)
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12+6/3x2-10 12+2x2-10 12+4-10 16-10 ANSWER= 6 :) Improved answer: 12+6/3x2-10 18/6-10 18/-4 18+4/-4+4 22/0 =22
(9x - 10)(x + 3)
Do you mean: 3x2-17x+10? If so then it is: (3x-2)(x-5)
3x2+13x-10 = (3x-2)(x+5) when factored
(x+1)(x+5)(x+2)
(3x + 2)(x + 5)
3x2 + 27x = 30 ∴ x2 + 9x - 10 = 0 ∴ (x + 10)(x - 1) = 0 ∴ x ∈ {-10, 1}
10
3x+y=5(4x-7y)=-10 3x+y=20x-35y=-10 -3x -3x y=17x-35y=-10 -y -y 17x-36y=-10 sorry but that's as far as i could get :(
This looks more like a factoring problem than a GCF problem. Since those three terms have nothing in common, the GCF is 1. But as an equation, it factors to (x + 5)(3x + 2)
Unfortunately, limitations of the browser used by WA means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals" etc.
12+6/3x2-10 12+2x2-10 12+4-10 16-10 ANSWER= 6 :) Improved answer: 12+6/3x2-10 18/6-10 18/-4 18+4/-4+4 22/0 =22
(9x - 10)(x + 3)
9/15[(3x + 15)(x - 1) + 21] / [(x + 6)(5x - 10) + 70]Limx→∞ (6x3 - 3x2 + 17x + 1) / (10x3 + 11x - 5)Because each of these has a numerator that is equal to three fifths of the denominator.